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A factory manufacturing flywheels for racing cars has 10 machines to make them. The manufacturer knows the correct weight for a flywheel.However, one day one of the machine begins to produce faulty parts- either overweight or underweight.How can the manufacturer find the faulty machine in only 2 weighings
Rathinavelu
- Oct 23rd, 2006
As Archana said, find y.For second weighing, take one sample from each machine and find its weight, let it be z, The weight of each sample is x, therefore the actual weight should be 10xfind (z~10x)&n...
Archana.G
- Oct 6th, 2006
Hi pooja,Proceed this way..........Take 1 fly wheel from 1st machine ,2 flywheels from 2nd, 3 from 3rd and so on 10 from the 10th machine.Now u will have a total of 55 wheels.just weigh them.say...
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Two women were selling marbles int the market place -- 1 at 3 for a paise and other at 2 for a paise. one day both of them were obliged to return home when each had 30 marbles unsold. they put together the 2 lots of marbles and handling them over to a friend asked her to sell them at 5 for 2 paise.now they were expecting to get 25 paise for the marbles as they would have got if sold separately but much to their surprise they go only 24 paise in total.where did the 1 paise go ? can anyone explain the mystery?
go2francis
- Oct 10th, 2006
Hi,If they sold separately,Woman 1 would have sold only Ten sets i.e. 3 * 10 = 30 piecesWoman 2 would have sold 15 sets i.e. 2 * 15 = 30 piecesBut when they are mixed their friend sold 12 sets i.e. 5 ...
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1/3 rd of the contents of a container evaporated on the 1st day. 3/4th of the remaining contents of the container evaporated on the day2. What part of the contents of the container is left at the end of the day2?
Let the original content be Xon first day, X/3 evaporates leaving 2X/3.on second day , 3/4 of 2X/3 evaporates which will leave 1/4 of 2X/3 = X/6 remains.
Bala
- Jul 25th, 2006
Let the content be X.1/3 of the content evaporated. 1/3 (X). The remaining content is X-1/3 (X)=2/3 (X).3/4 of the remaing content evaporated. 3/4(2/3 (X))=1/2(X).So the remainig content is 50%.
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Two train starts from two town for each hour. it takes 5hours to rach oter town.how many trains does the train come across.
Lucas
- Jul 3rd, 2006
The correct answer is 10 trains... Because Even before it starts already there will be four trains in track and afer the first train starts it will cross both this 4 previous trains and the next 6 trains in his journey...
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There is a 1 km long wire. It has been fixed around a wall of the building with the help of some poles between 2 telephone towers. It is noticed that if there is a increase of 1 2/3 m in width of 2 poles then there is a need of 1 pole less. How many poles were used?
How many Poles were used?
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A 1 Km wire is connected between N poles. if 1 pole is removed the distance between the pole increases by 2/3 of the original distance. How many poles are there?
tmhasan7
- Sep 25th, 2006
SIMPLE.....Step 1: Space between the two poles originally = 1000/(N-1) (If there are N poles there are N-1 Spaces)Step 2: One pole is removed. So the no of poles is N-1 and no of spaces is N-2. I...
naani
- Jan 16th, 2006
Please explain briefle??I am unable understand how u got the answer??
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Two railway lines intersect at right angles. Two Trains are racing at the same time towards that Intersection; one having left a station 40 kms from the intersection And doing 48 kmph and the other 50 kms from the intersection and doing 36 kmph. In how many hours after The start will th trains be Separated by the shortest distance and where ?
tirthas
- Jan 6th, 2006
The first answer is rt. The shortest distance between the two points is a strt line.
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fifty minutes ago if itwas 4 times as many minutes past 3'o clock.how many minutes is it to 6'o clock(SAK-2)I WANT THE COMPLETE SOLUTION
tmhasan7
- Sep 21st, 2006
Sorry the second point should be like this..2. 4 times time past 3 will be 4x(which is the time to reach 6 from now).
tmhasan7
- Sep 21st, 2006
(Hi Sapthagiri. If the present time is 5:14 then 50 min ago it ill be 4:24. This gives time past three as 104 min. 4 times of this will lead us beyond 6.)So check this out.. Its very simple. 1. Let th...
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Fifty minutes ago if it was 4 times as many minutes past 3o'clock.how many minutes is it to six o'clock
tmhasan7
- Sep 21st, 2006
Sorry the second point should be like this..2. 4 times time past 3 will be 4x(which is the time to reach 6 from now).
tmhasan7
- Sep 21st, 2006
Check this out.. Its very simple. 1. Let the time past 3 be x min. 2. 4 times how many minutes is it to 6'o clock will be 4x.3. Time between 3 and 6 is 180 min. 4. This 180 min includes x, 4x and 50. ...
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A + B + C +D = D + E + F + G = G + H + I =17. IF A = 4 WHAT ARE THE VALUES OF D AND G. EACH LETTER TAKEN ONLY ONE OF THE DIGIT FROM 1 TO 9.
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1 2 3 4 + 3 4 5 5 ---------- 4 6 8 9 - 2 3 4 5 ---------- 2 3 4 4 + 1 2 5 4 ------------ 3 6 9 8 ------------Q) Strike off any digit from each number in seven rows (need not be at same place) and combine the same operations with 3 digit numbers to get the same addition. After this strike off another digit from all and add all the No.s to get the same 2 digit No. perform the same process again with 1 digit No.s. Give the ' no.s in 7 rows at each stage.
kusuma_b
- Sep 14th, 2006
can any one please tell the procedure to find the solution.please give it clearly
vijay
- Apr 4th, 2006
Last two numbers are added wrongly
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