1/3 rd of the contents of a container evaporated on the 1st day. 3/4th of the remaining contents of the container evaporated on the day2. What part of the contents of the container is left at the end of the day2?

Let the original content be X
on first day, X/3 evaporates leaving 2X/3.
on second day , 3/4 of 2X/3 evaporates which will leave 1/4 of 2X/3 = X/6 remains.
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Geetanjali

  • Jun 28th, 2006
 

   1/3 of the contents is evaporated on day 1 and remaining part is 2/3

so 3/4(2/3) is 1/2 so amount left by the end of day2 is 50%

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Bala

  • Jul 24th, 2006
 

Let the content be X.1/3 of the content evaporated. 1/3 (X). The remaining content is X-1/3 (X)=2/3 (X).3/4 of the remaing content evaporated. 3/4(2/3 (X))=1/2(X).So the remainig content is 50%.

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