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Find Maximum Marks
. A candidate appearing for an examination has to secure 40% marks to pass paper I. But he secured only 40 marks and failed by 20 marks. What is the maximum mark for paper I?
ankit sarkar
- Feb 15th, 2016
150 marks
sneha562
- Jul 1st, 2011
Let us consider x is the maximumber number of marks.secured marks => 40% of x= 40/100 of x=2x/5To pass an exam he has to score =fail marks+20 =40+20=60 2x/5=60 x=150maximum marks for paper I is =150
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What is the Number of zeros at the end of the product of the numbers from 1 to 100
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A man walks at a speed of 4km/hours
A man walks at the speed of 4km per hour from point A to B and comes back from point B to A at the speed of 8km per hour. What is the ratio between the time taken by man from point A to B and B to A?
pratik jadon
- Sep 10th, 2010
From A to Btime1=dist./4;From B to Atime2=dist./8;time1/time2=8/4;time1/time2=2;;ans. is 2...
maxz71
- Sep 8th, 2010
4 km/hr from A to B = s1
8 km/hr from B to A = s2
Speed = Distance/Times1 = d1/t1
s2 = d2/t2
s1/s2 = t2/t1 We need t1/t2 so,
Answer ratio is 2:1
Check if its correct.. -
1/3 of a Number
1/3 of a number is 3 more than 1/6 of the same number. What is the number?
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The number 362 in decimal system is given by (1362)x in the X system of numbers find the value of X a}5 b) 6 c) 7 d) 8 e) 9
saurabh
- Mar 1st, 2016
Answer is b) 6
farzad_af
- Apr 4th, 2009
6 is not a feasible answer for this problem, notice there is a "6" in the numbernone of answers is correct
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A work is done by two people in 24 min. one of them can do this work a lonely in 40 min. how much time required to do the same work for the second person.
In 1 minute (A+B) can do 1/24 work. A alone can 1/40 work in 1 minuteB alone can do in 1 minute = (A+B)’s – A’s = 1/24 – 1/40 = 1/60 workTherefore, b can do the same work in = 60 min
bharathmarri
- Jul 8th, 2009
Let A can do a work alone in 40 mins [Given]=> amt of work done by A in 1 min = 1/40Let B can do the same work alone in 'b' mins=> amt of work done by B in 1 min = 1/bthen, amt of work d...
bharathfeb
- Jul 7th, 2009
Let A does a work in 40 mins [Given]=> work done by A in 1 min = 1/40Let B can do the same work in 'b' mins=> work done by B in 1 min = 1/bThen, work done by A & B in 1 min = 1/40 + ...
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A person was fined for exceeding the speed limit by 10mph. Another person was also fined for exceeding the same speed limit by twice the same. If the second person was traveling at a speed of 35 mph, find the speed limit.
Let ‘x’ be the speed limit. Person ‘A’ was fined for exceeding the speed limit by = 10mphPerson ‘B’ was fined for exceeding the speed limit by = twice of ‘A’ => 2*10mph=20mphgiven that the second person was traveling at the speed of 35mph => 35mph – 20mph = 15mphTherefore the speed limit is =15 mph
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A 0 0 0 0 1 1 1 1B 0 0 1 1 0 0 1 1C 0 1 0 1 0 1 0 1Find ( A u B ) n C
sagarpdy
- Jun 26th, 2009
It is one of the representation of setsi.e.?A={0,1,2,3}likewisehence A U B = A|B=00111111(AUB)nC= (AUB)&C=00010101Ans={0,2,4}
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If A,B,C are the mechanism used seperately to reduce the wastage of the fuel by 30%, 40%, 10% What will be the fuel economy if they were used Combined?
A. 68.4
B. 62.2
C. 58
D. 27
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mnotageek- Member Since Jul-2007 | Jul 19th, 2007
ok let us suppose 100 kg of fuel is being wasted.. if i use the A then 30 kg will be saved n 70 kg will be wasted. now if i bring in B it will save 40% of 70 n (70*0.6)=42 kg will be wasted. Now if i incorporate C then it will save 10%of 42 i.e..,(42*0.9) 37.8 kg will be wasted... so 100-37.8=62.2 kg will be saved.. so ans is 62.2%
Anirudh Dayma
- Jul 11th, 2017
Assume total =100 then 30% = 70, 40% reduction = 3/5 and 10% reduction = 9/10. Therefore total reduction = 70X(3/5)X(9/10) = 37.8 therefore ans = 100 - 37.8 = 62.2
Mudit
- Jan 24th, 2017
How can you apply efficiency on wasted fuel?
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Present Age Calculation
Three years ago, the average age of A, B and C was 27 years and that of B and C, 5 years ago was 20 years. A's present age is?
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A bus started from bus stand at 8.00am, and after 30 minutes staying at destination, it returned back to the bus stand. The destination is 27 miles from the bus stand. The speed of the bus is 18mph. In return journey bus travels with 50% fast speed. At what time it returns to the bus stand?
11.00am
chetna
- Jun 11th, 2024
A bus started from bus stand at 8.00am, and after staying for 30 minutes at a destination, it returned back to the bus stand. The destination is 27 miles from the bus stand. The speed of the bus is 18...
Hirs_belive_apti
- Sep 25th, 2008
Total time taken by it is following :1.5 (to reach at destination) + 0.5 ( talking halt at station) + 1 (return with 50% speed)so the total time taken by it is 3 hrcurrent time is 8.00 a.m + 3 hr = 11 a.m.So 11 a.m. is the right answer
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Low temperature at the night in a city is 1/3 more than 1/2 high as higher temperature in a day. Sum of the low temperature and highest temp. is 100 degrees. Then what is the low temp?
40 deg.
jagds
- Aug 13th, 2010
Low temp=Xhigh temp=Ythan X=1/2(Y) + 1/3[1/2(y)]X=2/3(Y)We have X+Y=100Two equatios3X-2Y=0X+Y=100So...X=40....
neeti tripathi
- Dec 14th, 2009
The answer should be 33.5 As there are two equation L+H=100andL=1/3 + 1/2(H)so we getL= 1/3 + 1/2(L-100)Which gives L= 33.5 approx.
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Two pencils costs 8 cents, then 5 pencils cost how much ?
2 pencils = 8 cents => 1 pencil = 4 cents. Therefore 5 pencils cost = 5 * 4 = 20 cents
pravesh28
- Feb 27th, 2010
It has different ans may be 40 cent (one get one free?20 cent only when both pencil has same price
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A moves 3km. east from his starting point,he then travels 5km north,from that point he moves 8kms to the east. how far is A from his starting point?if a student scores GPA in his sem & year as given below then calculate his GPA for 3 year.sem 2.4,3.4yr 1.3,1.9bbgmpqbgskobgasbbgdefbgsti how many b's are follwed by g's which are not follwed by s in the above series?M(373,5)+r(3.4)+t(7.7)-r(5.8)=?t=truncation ,r=round-offplzz tell me the procedureplzz tell me all these solutions ..its very urgent!!!!!1
isha verma
- Nov 24th, 2010
M(373,5)=373/5which gives remainder as 3r(3.4)=3t(7.7)=7r(5.8)=6so, 3+3+7-6=7Hence 7 is the ans
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Missing Terms
Find the right number, from the given options, at the place marked by the question mark: 2, 4, 8, 32, 256, ?
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Editorial / Best Answer
aravinthan2k6- Member Since Dec-2007 | Aug 16th, 2009
Each of the preceding number is multipied by the previous number
So on multiplying 2*2 = 44*2 = 88*4 = 3232*8 = 256256*32 = 8192so the answer for this series is 8192 -
1. In a two dimensional array X(9,7) with each element occupying 4 bytes of memory with the address of the first element x(1,1) is 3000,find the address of X(8,5) ? Ans is 3212 but how explain2.194 base 10= ___ base 53.the base 5 representation of the decimal number 2048 is______4.when 3/4 of a units digit is added to ten's digit of a two number,the sum of the digit becomes 10.If 1/4 of the ten's digit added to the unit's digit then the sum of the digits is 1 less than the previous.Find the number a)94 b)84 c)48 d)88
brahmam
- Oct 21st, 2014
3012
bansal_yogesh_it_1985
- Jun 20th, 2010
deviravikumar,If X(1 2) = 3004 then how can X(1 7) = 3042 I think X(1 7) = 3024and if X(2 1) 3046 then how can X(2 7) = 3052I think it should be X(2 7) = 3070
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1.If g (0)=g (1)=1And g (n)= g (n-1) + g (n –2) find g (6);tell me the solution
tanmoytt
- Aug 14th, 2010
G(6)=g(5)+g(4)g(5)=g(4)+g(3)g(4)=g(3)+g(2)g(3)=g(2)+g(1)g(2)=g(1)+g(0)=1+1=2S0, g(3)=2+1=3g(4)=3+2=5g(5)=5+3=8g(6)=8+5=13
Noob1
- Aug 13th, 2010
G(6)= g(5)+g(4)g(4)= g(3)+g(2)g(2)= g(1)+g(0)= 2 (Given in ques g(0)=g(1)=1)So, g(3)= g(2)+g(1)= 2+1= 3Also, g(4)= g(3)+g(2)= 3+2= 5Similarly, g(5)= g(4)+g(3)= 5+3=8And hence, g(6)= g(5)+g(4)= 8+5= 13 -ANS
Quantitative Aptitude Questions
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