chandradeepika

 Profile Answers by chandradeepika Questions by chandradeepika

• May 27th, 2008

 

let x,y and z be the angles of 3 sides.
given: x=3y; z=y+20.  y=?   
we know the total angle of the triangle is 180 deg. therefore x+y+z=180.
on substituting the given conditions  we get
3y+y+y+20=180
5y=160
y=32.
therefore the second angle isy=32 deg.

mohit.thekiller

 Profile Answers by mohit.thekiller 

• Sep 21st, 2008

 

let 2nd angle =x    then 1st one is =3x    3rd is =x+20    n now  x+3x+x+20=180   therefore x=32

madhurimasridhar

 Profile Answers by madhurimasridhar 

• Mar 5th, 2009

 

Suppose the second angle is x deg.
First angle is 3 times of the second angle so first angle is 3x deg.
Third angle is 20deg more than the second so.. third is x+20 deg
Sum of angle in triangle is 180 deg = x+3x+(x+20) = 5x+20
So second angle is 32deg.

pawansharma1987

 Profile Answers by pawansharma1987 

• Mar 14th, 2009

 

3x + x+ (x+20) =180

x= 32 degrees

bipurag

 Profile Answers by bipurag 

• Apr 19th, 2009

 

First step:let the second angle be:x
Therefore the first angle:3x
and third angle becomes:x+20
Therefore ATQ
X+3X+X+20=180(As the three side of the angle total is 180)
5x=160
x=32
so,The second angle is 32