Uday Kumar. A

 Profile Answers by Uday Kumar. A Questions by Uday Kumar. A

• Oct 8th, 2006

 

I think it will return compile time error, because the syntax

JavaWindow("Trade Manager").JavaDialog("Trade Entry").JavaButton("Enter").Exist 10

 

shyam

• Oct 8th, 2006

 

What is the maximum amount of time the statement will wait for the
specified object to appear?

A 20 seconds

B 10 seconds

C 30 seconds

D 10 milliseconds

E 20,010 milliseconds

Answer is A

Senthil Kumar P

• Oct 11th, 2006

 

Hi

If it's syntax is correct it will wait for 30 seconds.

Synchornazation point waiting time is

time in run settings(here 20 seconds) +time mentioned in script(here 10 seconds)= so 30 seconds is answer 

muralisqa

 Profile Answers by muralisqa Questions by muralisqa

• Oct 11th, 2006

 

Hi

1). If u specify timeout value 10 sec after exit command it waits for 10 seconds only.

Eg: JavaWindow("Trade Manager").JavaDialog("Trade Entry").JavaButton("Enter").Exist 10

2). If the time out value is 0 it doesn't wait for the button.

Eg:JavaWindow("Trade Manager").JavaDialog("Trade
Entry").JavaButton("Enter").Exist 0

3).If the timeout value u specify Blank it waits upto completion of default

 time out(20,000ms) 20 sec. 

Eg:JavaWindow("Trade Manager").JavaDialog("Trade
Entry").JavaButton("Enter").Exist

any errors plz mail me.

Nadeem Sharifuddin

• Jan 2nd, 2007

 

QTP will wait for maximum 30 seconds

before show error , if button does not exist.