vinayak

• Sep 28th, 2006

 

ans is  1344

naveen

• Sep 30th, 2006

 

Ans is 1344 and it is calculated asfirst add 8 since in first row 8 elements then for the next 3 row add 9 nd for the last row add 8 so the total comes to 43 multiply with 2 add it to 1258 it gives 1344

ajay

• Oct 5th, 2006

 

it should be 1330 according to me

joseprabhu

• Oct 5th, 2006

 

Hi ,

Can any one explain this with proper steps

vishal

• Nov 30th, 2006

 

intger req. 2 byte for memory allocation so in this two dim array 7x9 it req. 126 bytes memory.

so 1x1 starting add is 1258.

now to find add of 5x8 so it req 80 byes

so 80+1258=1338.

prashant kara

• Jan 24th, 2007

 

here, the address of first element x[1][1] is 1258 and also 2 byte of memory is given.now, we have to solve the address of element x[5][8], therefore, 1258+ 5*8*2 = 1258+80 = 1338 so the answer is 1338.

imran4108

 Profile Answers by imran4108 

• Apr 26th, 2008

 

formulae is
X(5,8)=X(N,M)
X(7,9)=X(R,C)
X(5,8)=BASE+C*(M-1)*SIZE+(N-1)*SIZE
WHERE SIZE=2BYTES
BASE=1258
X(5,8)=1258+9*7*2+4*2

bangalo

 Profile Answers by bangalo 

• Aug 4th, 2010

 

The answer is

1) If it is a row based then

1258+2(9(5-1)+(8-1))=1258+2(36+7)=1258+86=1344

2)
If it is column based then

1258+2((7(8-1)+(5-1))=1258+2(49+4)=1258+106=1364.

ankita_kri

 Profile Answers by ankita_kri 

• Aug 5th, 2010

 

1258+4*(9*(5-1)+(8-1)) equals to 1430