A ship leaves on a long voyage. When it is 18 miles from the shore, a seaplane, whose speed is 10 times that of the ship is sent to deliver mail. How far from the shore does the seaplane catch upo with the ship?

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Jul 13th, 2006
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uday reddy

Jul 30th, 2006

time taken is same for both the ships & seaplanetime =distance/speed.....if speed of ship=s then seaplane speed=10slet distance of ship be x then seaplane distance =18+xtherefore (x / s = (18 + x ) / 10s)...then we get x = 2 therfore total distance = 18+2=20ans 20

microelectronics
Profile Answers by microelectronics

Jan 2nd, 2010

Consider the speed of ship be a then the speed of plane is 10a;
Let t be the time taken by the ship to travel 18 miles then a= 18/t;
Speed of plane =180/t;
Distance covered by the ship during next t' time = 18+ 18*t'/t;
Distance covered by sea plane = 180*t'/t;
Equating both 162*t'/t =18 ;
t'/t = 18/162;
Distance to be covered = 180* 18/162 =20 miles ;