Anand finishes a work in 7 days, Bittu finishes the same job in 8 days and Chandu in 6 days. They take turns to finish the work. Anand on the first day, Bittu on the second and Chandu on the third day and then Anand again and so on. On which day will the work get over? a) 3rd b) 6th c) 9th d) 7th

This question is related to TCS Interview

Interview Candidate
Jul 13th, 2006
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sultan

Jul 25th, 2006

Ans is d) 7th day
In d 1st day Anand does 1/7th of total work
similarly,
Bithu does 1/8th work in d 2nd day
hence at d end of 3 days, work done = 1/7+1/8+1/6=73/168
remaining work = (168-73)/168 = 95/168
again after 6 days of work, remaining work is = (95-73)/168 = 22/168
and hence Anand completes the work on 7th day.(hope u understood.)

Vivek Shah

Sep 22nd, 2006

let thet speed of ship is =v
so seaplane speed must be=10v
let seaplane catch the ship in t time
so in t time ship moves x distance
so x/v=(x+18)/10v
x=2
so distance =18+2=20

parmeet singh

Oct 18th, 2006

yarr it's not as difficult as it looks
see
the fastest guy takes 6 days if he is handeling alone ,but it is not hence option for 6 and 3 days is eleminated.
the slowest guy takes 8 days rest all are are fast so there is no way target will go over to 9 days
hence the only option is 7 days