A rich man wanted to distribute his collection of gold coins among his ten children comprising of 5 sons and 5 daughters. He also wanted to give some coins to his car driver. He proceeds on the following basis. The first coin went to the car driver and then 1/5th of the remaining coins to his first son. He then gave another coin to the car driver and distributed 1/5th of the remaining coins to his second son. This procedure went on till all the five sons received their share. Once all the sons received their shares, he distributed the remaining coins equally among his daughters. Can u find how many gold coins the rich man had? Ans i think is 881

This question is related to Infosys Interview

Interview Candidate
Dec 7th, 2005
2
2200

Showing Answers 1 - 2 of 2 Answers

Himanshu

Dec 8th, 2005

i think the question z incomplete but equation that i am getting is
let 5th son receives 'y' coins then
4th son's share=1+5y
3rd=6+25y
"
1st=155+625y
then the old man has 156+625y(this is boys share)
if y=1 than old man had 781
if one girl is getting 20 coins than total coins that old man had 881
so i m getting the same ans.

premaa
Profile Answers by premaa

Jul 21st, 2010

Total Coins = 3121.
3121 = (3121-1), (3120 * 1/5), (2496-1), (2495 * 1/5), (1996-1), (1995 * 1/5), (1596-1), (1595 * 1/5), (1276-1), (1275 * 1/5), 1020
Now divide in girls equaly = 1020 / 5 = 204 coins to each