thana

• Aug 27th, 2005

 

HI, 
I cannot find out most of the answers. Can anyone please suggest me a good book on aptitude.l

Gagan

• Feb 3rd, 2006

 

AM=Mr. Aye

AF= Mrs. Aye

BM=Mr. Bee

BF=Mrs. Bee

The possible sequence of matches can be :

AM(Win) Vs.AF

AM(win) Vs. BM

AM Vs. BF(win)      Hence Mrs. Bee never lose. 

rohith

• Feb 28th, 2006

 

mr and mrs bee has wone 2 games winning the series

Jyoti

• Oct 13th, 2006

 

Hi,

R.S.Agarwal and Baron this two books are good for apittude........

Google

• Oct 27th, 2006

 

In three games, men won more games than women (therefore, at least 2), and Ayes won more games than Bees (therefore, at least 2). Also, if a player lost, s/he did not play the next game. Therefore, Mr. Aye must have won his game (Ayes 1, Bees 0; Men 1, Women 0). Mrs. Aye is out.For the Ayes to win 2 games, Mr. Aye must have won the second game. (Ayes 2, Bees 0; Men 2, Women 0)In order for a woman to win a game, Mrs. Bee must have won her game against Mr. Bee (Ayes 2, Bees 0; Men 2, Women 1).So Mr. Aye never loses. Duh.

Al

• Nov 2nd, 2006

 

this puzzle is from george j. summers "puzzles and teasers'Answer is Mrs Bee,,, george has given a confusing and long explaination,, here is my versionMr aye beat mrs aye in first game (bee cant be playing since ayes are supposed to win more games, if one of them is out, then even if both ayes can win against the remaining bee, it violates the other conditions,, think,,,)now two casesmr aye vs mr bee >> winner mr aye (aye win more games than bee)mr aye vs mrs bee >> winner mrs bee (women win atleast one game)hence mrs bee playes the finalist and beat him,,,,

swarna

• Dec 26th, 2006

 

1-Mr and Mrs aee (Mr Aee wins)

2-Mr Aee and Mr Bee (Mr Aee wins)

3-Mr Aee and Mrs Bee (Mrs Bee)

Men wins twice,Women once.

1st game played by couples Mr and Mrs Aee

Abhishek Anand

• Apr 22nd, 2015

 

BM(win) vs BF
AM vs BM(win)
BM vs AF(win)
AF never loses a game.

Gaurav.khurana

 Profile Answers by Gaurav.khurana 

• Apr 25th, 2015

 

@anand you missed one condition that Aye win > Bee win
In your solution , B winning > A winning
so the solution as listed above is M=male F = female
1) AM(win) -- AF ( first match is couple)
2) AM(win) - BM ( second match aye win 2 matches out of 3)
3) BF(win) - AM ( AF and BM cannot play as they lost matches. also women won 1 match)
hence Mrs Bee (BF) did not loose a game

suman

• May 21st, 2016

 

BM VS BF(WIN)
AM(WIN) VS BF
AM (WIN) VS BM
So,AM never loses a game..
*it is not mandatory that everyone has to participate in the game,so AF didnt take part in that game

Zoetrinity

• Jun 17th, 2024

 

Given Constraints:
1. Only in the first game were the two players married to each other.
2. The men won two games and the women won one game.
3. The Ayes won more games than the Bees.
4. Anyone who lost a game did not play the subsequent game.
Scenario Analysis:
First Game (Married Couples):
1. Mr. Aye vs. Mrs. Aye
2. Mr. Bee vs. Mrs. Bee
Scenario 1: Mr. Aye vs. Mrs. Aye in the First Game
- If Mr. Aye wins, Mrs. Aye is out.
- If Mrs. Aye wins, Mr. Aye is out.
Sub-Scenario 1.1: Mr. Aye wins against Mrs. Aye
- Mrs. Aye is out.
- Remaining players: Mr. Aye, Mr. Bee, Mrs. Bee.
Second Game:
- Mr. Aye plays against Mr. Bee:
- If Mr. Aye wins, Mr. Bee is out.
- If Mr. Bee wins, Mr. Aye is out.
1. Mr. Aye wins against Mr. Bee:
- Mr. Bee is out.
- Remaining players: Mr. Aye, Mrs. Bee.
Third Game:
- Mr. Aye plays against Mrs. Bee:
- If Mr. Aye wins, men win all three games (invalid, as women must win one game).
- If Mrs. Bee wins, men win two games, and women win one game, satisfying the condition.
Thus, if Mrs. Bee wins the third game, we have:
- First game: Mr. Aye wins.
- Second game: Mr. Aye wins.
- Third game: Mrs. Bee wins.
This satisfies:
- Men won two games.
- Women won one game.
- The Ayes won more games than the Bees.
In this sequence, Mrs. Bee did not lose any game.
Sub-Scenario 1.2: Mrs. Aye wins against Mr. Aye (Invalid)
- Mr. Aye is out.
- Remaining players: Mrs. Aye, Mr. Bee, Mrs. Bee.
Since this sub-scenario doesnt align with the given conditions (Ayes winning more games), we discard it.
Scenario 2: Mr. Bee vs. Mrs. Bee in the First Game
- If Mr. Bee wins, Mrs. Bee is out.
- If Mrs. Bee wins, Mr. Bee is out.
Sub-Scenario 2.1: Mr. Bee wins against Mrs. Bee
- Mrs. Bee is out.
- Remaining players: Mr. Bee, Mr. Aye, Mrs. Aye.
Second Game:
- Mr. Bee plays against Mr. Aye:
- If Mr. Bee wins, Mr. Aye is out.
- If Mr. Aye wins, Mr. Bee is out.
1. Mr. Bee wins against Mr. Aye:
- Mr. Aye is out.
- Remaining players: Mr. Bee, Mrs. Aye.
Third Game:
- Mr. Bee plays against Mrs. Aye:
- If Mr. Bee wins, men win all three games (invalid, as women must win one game).
- If Mrs. Aye wins, men win two games, and women win one game.
Thus, if Mrs. Aye wins the third game, we have:
- First game: Mr. Bee wins.
- Second game: Mr. Bee wins.
- Third game: Mrs. Aye wins.
This scenario is invalid because the Bees won more games than the Ayes. So, discard this.
Sub-Scenario 2.2: Mrs. Bee wins against Mr. Bee
- Mr. Bee is out.
- Remaining players: Mrs. Bee, Mr. Aye, Mrs. Aye.
Second Game:
- Mrs. Bee plays against Mr. Aye:
- If Mrs. Bee wins, Mr. Aye is out.
- If Mr. Aye wins, Mrs. Bee is out.
1. Mr. Aye wins against Mrs. Bee:
- Mrs. Bee is out.
- Remaining players: Mr. Aye, Mrs. Aye (invalid as per constraint a).
Since Mr. Aye and Mrs. Aye cannot play against each other in the third game, this scenario is invalid.
Conclusion
Only Sub-Scenario 1.1 is valid:
- First game: Mr. Aye wins against Mrs. Aye.
- Second game: Mr. Aye wins against Mr. Bee.
- Third game: Mrs. Bee wins against Mr. Aye.
Thus, the player who did not lose any game is:
Mrs. Bee.