Partha

• Jun 30th, 2006

 

The value of G is 2

GajendraC

 Profile Answers by GajendraC 

• Jan 22nd, 2010

 

As given
A*B*C=B*G*E=D*E*F
hence
A*B*C=B*G*E-------(1)
B*G*E=D*E*F--------(2)
from 1
=> G=AC/E
and from 2
=>G=DF/B
since
AC/E=DF/B----------(3)
Here we have 0 to 9 numbers  so we arrenge the numbers in equation 3 as it satisfy

so 3*6/9=2         so value of A and C should be 3and 6, And E=9
And 1*8/4=2       n value of  D and F should be 1 and 8 and B=4

so the value of G is 2

 

GajendraC

 Profile Answers by GajendraC 

• Jan 22nd, 2010

 

The value of g is 2 and

A*B*C =B*G*E=D*E*F=72

priya

• Sep 11th, 2018

 

How did you take the Values of A and C,D and F...is it taken randomly?...Please reply the answer

Zoetrinity

• Jun 17th, 2024

 

As given A*B*C=B*G*E=D*E*F
hence A*B*C=B*G*E-------(1)
B*G*E=D*E*F--------(2)
from 1=> G=AC/E and from 2=>G=DF/B
since AC/E=DF/B----------(3)
Here we have 0 to 9 numbers, so we arrange the numbers in equation 3 that will satisfy equation 1&2.
so 3*6/9=2
so value of A and C should be 6 and 3, And E=9
And 1*8/4=2
so value of D and F should be 8 and 1 and B=4
so the value of G is 2

2. Trial with Possible Values:
- Try assigning values that will make the products equal while keeping digits distinct.
Assume 72 because more than 72 not possible for two sides
A*B*C = B*G*E = D*E*F
6*4*3=72
4*2*9=72
8*9*1=72
A = 6
D = 8
B = 4
G = 2
E = 9
C = 3
F = 1
G represents the digit 2.