Shwetha N A

• Jun 25th, 2021

Tail +25 filename | head -1

Ashok

• May 27th, 2018

Sed -n 25p filename.txt

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Write a script to validate a password. The password should be least 8 characters long, should contain both alphabet and number, contain small cap and large cap letters. If any of these conditions are not met, the script should flag the password as "weak password".

Shwetha N A

• Jun 24th, 2021

#!/bin/bash
echo "Enter the password"
read password
len=echo ${#password}
if test $len -gt 8
then
echo $password | grep [A-Za-z][0-9] | grep "[@#$%^&*]"
echo "strong password"
else
echo "weak password"
fi

Akshay Deshmukh

• Sep 14th, 2020

read -p "please enter password:" password count=`echo ${#password}` if [[ $count -ne 8 ]];then echo "Password length should be 8 charactore" exit 1; fi echo $password | grep "[A-Z]" | grep "[a-z...

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Shrey Shekhar

• Sep 5th, 2020

Cat file_name|uuencode file_name|mail -s subject line reciepent_email_address

vishnu

• Aug 1st, 2017

Using mutt, mailx, or uuencode

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Sathish Krishnan Venkatachalam

• Aug 7th, 2020

Grep "^$" file.txt

mallikarjuna reddy

• Jul 23rd, 2019

Grep -n ^$ file1.txt this command will give the all empty lines numbers display
grep -n ^$ file1.txt | wc -l this command will give the all empty lines number counts in file

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You have current directory containing set of directories which contain files.One file can reside in many directories.Write script which returns number of unique file names inall the subdirectories of a current dir.

Sathish Krishnan Venkatachalam

• Aug 7th, 2020

Ls -lR | awk /^-/ {print $NF} | uniq

sonu

• Mar 1st, 2018

Find . -type f | awk -F / { print $NF } | sort | uniq -c

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How to print nth column of a pattern/file without using awk,cut commands?

Sathish Krishnan Venkatachalam

• Aug 7th, 2020

I hope the below answer, to retrieve 3rd column without using awk (or) cut, use the following command:
sed s/^(.*) (.*) (.*) (.*)$/3/g file.txt
insert or delete "(.*)" based on which column to be retrieved and change "3" to nth column no.

Ashok

• May 27th, 2018

Sed -n np file.txt

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In shell scripting How to indentify that the previous command was run successfully?

Yogesh

• Oct 4th, 2017

Echo $?
if answer 0 then last command was successful.
if answer is any numeric value then last command is not successful.

abdas

 Profile Answers by abdas Questions by abdas

• Jun 26th, 2011

in 2 ways it can be done:1st way$ echo $?  2nd way:$ pwd 2> error| cat error|wc -l       0$ cat h 2> error| cat error|wc -l       1pwd or cat or any command if outpt is 0 then successful else failed.

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anil

• Sep 21st, 2017

upendram@upendrams-host:~$ echo $pattern | grep -o . | while read chars; do cnt=`echo "${str}" | grep -o "${chars}" | wc -l`; if [[ $cnt -gt 0 ]]; then echo "$chars -- occurs --- $cnt times" >> strin...

rana4bhu

 Profile Answers by rana4bhu Questions by rana4bhu

• Jun 5th, 2009

I am giving the 3 ways to solve this problem..1) grep -io "[aeiouAEIOU]" filename | sort | uniq -c2) cat filename | sed 's/[a-zA-Z]/&n/g' | sed 's/^ //' | grep "[aeiouAEIOU]" | sort | uniq -c 3) cat f...

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Want to delete the record if I find a word (dd)in the length(5-7). Lets think that (5-7) length is FF2.
This is a fixed width file.

ex f1

ff1 ff2 ff3
sds dd fd
sd ss ew
dd dd se

o/p should be like


ff1 ff2 ff3
sd ss ew

pranav Rakesh

• Sep 26th, 2017

Sed /[dD]$/d file

shailesh chanderiya

• Aug 26th, 2017

Line_no=` sed -n /^...*dd/=;p temp | sed -n /^[0-9]/p |xargs|sed s/ /d;/g;s/$/d/`
sed -i "${line_no}" temp

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In UNIX delete previous line if current line contains particular keyword

Mahender Lal

• Sep 3rd, 2017

Prev_line=`grep -B1 "Keyword_to_search" filename | head -1` ; grep -v "$prev_line" filename
prev_line=`grep -B1 "Keyword_to_search" filename | head -1` ; grep -v "$prev_line" filename > newfile

Yogesh

• Aug 31st, 2017

Grep-B1 "particularword" filename | rm

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Search "DD/MM/YYYY HH:MM:SS" in a file & this format needs to provide input value while executing & remove all the content whatever is before the input value in a file

Eg : #myscript.sh 31/10/2015 10:15:22

Mahender Lal

• Sep 3rd, 2017

To search "DD/MM/YYYY HH:MM:SS" in a file
grep -Eo [0-9]{2}/[0-9]{2}/[0-9]{4} [0-9]{2}:[0-9]{2}:[0-9]{2} file

Yogesh

• Aug 31st, 2017

Ls -ls * | grep "19/01/1989"

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In bash scripting, write a script for the following requirements.
Script in the name of script1.sh. Run this script in every 5 minutes. Before executing second time verify first time executed command status whether it was executed success or not.

Yogesh

• Aug 31st, 2017

If [ [find. -type -f -ctime+1 -print]=="" ] then
call any function. #call script in function##
fi.

kumar

• Jul 4th, 2017

I want to confirm whether my previous day file processed in sftp server then my current date current date script should start. In what way can we have a check whether previous day file processed. please help me in this.

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Manisha Kumari

• Jun 15th, 2017

In Esc mode, dw

sambit

• Mar 28th, 2017

Sed command with -i option will make the changes persistent in the file. You dont need the redirection operator to submit the changes to a new file. The answer is:

sed -i s/word_to_delete/word_to_replace_with/g file_name

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Write a small shell script that adds an extension ".new" to all the files in a directory.

Nawaz

• Jun 9th, 2017

For f in *; do mv $f ${f}.new; done

Nawaz

• Oct 25th, 2016

For item in `ls`; do mv $item ${item}.new; done

Code
 

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How to read the contents of fie inside jar without extracting in shell script?

Jegadeesan Ramu

• Jun 5th, 2017

Tar -tvf [file-name]

Reema

• Aug 27th, 2011

You can read the contents of file inside jar without extracting in shell script by using:

tar -tvf file.tar

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Nasirjamal MohdSiraj

• May 25th, 2017

Head -2 test | tail -1

Tarun Thakur

• Mar 28th, 2017

Sed -n 2p filename

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armaan mahajan

• May 22nd, 2017

#!/bin/bash

echo "please enter the string"

read string

string_new=$string

reverse_string=`echo $string|rev`

if [ $reverse_string -eq $string_new ];

then

echo "String is palindrome"

else

echo "string is not palindrome"

fi

sujit kumar

• May 4th, 2017

#!/bin/bash
echo -n "Enter a string: "
read str
if [ $(echo $str | rev) = $str ]
then
echo "$str is palindrome."
else
echo "$str is not palindrome"

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Gaurav Sharma

• May 16th, 2017

Use the below statement in program body.
echo $*|rev

anu

• Sep 16th, 2015

#!/bin/sh
#to print arguments in stdin in reverse order
for token in `echo $*| rev`
do
echo $token
done

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sambit

• Mar 28th, 2017

You dont need /g at the end for removing only the nth occurrence. You need g for replacing globally. The answer is:

sed s/string_to_replace/string_to_replace_with/n file_name

where "n" is the position where you want to do the replacement.

pankaja das

• Jan 30th, 2015

Sed s/xyz/n/g filename

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Ravindar

• Jan 2nd, 2017

Vi -R filename
This will open the file in read mode in vi editor(which is available in almost all unix version)

Akula Uday

• Nov 24th, 2016

View filename

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