Jitu

• Feb 9th, 2007

 

Hi All,
You can use this command:-
$ echo "$@" | rev
Please make me clear if i am wrong.
Thanks,
Jitu

Amit

• Aug 12th, 2007

 

i=$#
while(($i>=0))
do
echo $i
((i=$i-1))
done

kamalakar Navana

 Profile Answers by kamalakar Navana 

• May 27th, 2008

 

str="A B C D E F G"
echo $str | awk '{
for(i=length($0);i>=1;i--)
printf("%s",substr($0,i,1));
}'

UncaAlby

 Profile Answers by UncaAlby 

• Nov 7th, 2008

 

str="alpha beta gamma"
echo $str | awk '{
for (i=NF; i>0; i--) printf ("%s ",$i);
printf("n");
}'

Results:

gamma beta alpha

If you're talking about parameters passed into a Shell script, that can be modified to the following:

echo $* | awk '{
for (i=NF; i>0; i--) printf ("%s ",$i);
printf("n");
}'



The previous answer using "awk" reversed all the characters, resulting in:

ammag ateb ahpla

Which I don't think is what was meant in the phrase, positional parameters.

Although, if reversing all the characters is what you wanted, then that's one good way to do it.

my_thoughts

 Profile Answers by my_thoughts 

• Feb 14th, 2010

 

rev reverses individual argument and not the positions of set of arguments.

grohde

 Profile Answers by grohde 

• Jan 4th, 2011

 

Try this shell only version (uses Korn shell):

i=$#

while [[ $i > 0 ]]
do
  eval echo '$'$i
  ((i=$i-1))
done

grohde

 Profile Answers by grohde 

• Jan 4th, 2011

 

How about recursively.  Assuming a script named revarg.sh:

#!/bin/sh

arg=$1

if [ $# -gt 1 ]
then
  shift
  ./revarg.sh "$@"
fi

echo $arg

abdas

 Profile Answers by abdas 

• Jul 26th, 2011

 

$ cat rev2
i=$#
echo "$@" > file_1

while [ $i -gt 0 ]
do
cut -f $i -d" " file_1 >> file_2
i=`echo $i-1|bc`
done

echo `cat file_2`;
rm -f file_1 file_2;

$ sh rev2 A B C D E
E D C B A

shilpa keesara

• Aug 7th, 2011

 

Using KSH while loop#!/bin/ksh
#Get the count of total number of arguments passed while executing this script
int i = $#; #total number of arguments passed#
names=$@; #list of actual arguments passed#
while [ ${i} -gt 0 ]
do
echo '${names[i]}';
i=`expr i - 1`;
done
exit 0;

vish

• Aug 4th, 2014

 

Code
span style="color: #339933;">#; c>=1; c-- ))

eric

• Sep 10th, 2014

 

Code
span style="color: #339933;">#;c>0;c--))

Mayank Mishra

• Sep 15th, 2014

 

for((c=$#;c>0;c--))
do
eval echo -n "$$c "
done

aaseem

• Sep 21st, 2014

 

a=$#;
while [ $a -gt 0 ]
do
eval echo $$a
a=`expr $a - 1 `
done

gmatri

• Oct 20th, 2014

 

Code
count=$#   

abdul

• Nov 7th, 2014

 

i=$#

while [ $i -gt 0 ]
do
echo `echo "$*" | cut -d " " -f $i`
i=`expr $i - 1`
done

Mohit

• Nov 14th, 2014

 

Code
echo "$*"" " }} ;

Vishal

• Jan 27th, 2015

 

Code
len=`echo $#`

Sanjeev

• Apr 3rd, 2015

 

echo "$*" | rev

anu

• Sep 16th, 2015

 

#!/bin/sh
#to print arguments in stdin in reverse order
for token in `echo $*| rev`
do
echo $token
done

Gaurav Sharma

• May 16th, 2017

 

use the below statement in program body.
echo $*|rev