How do I declare inout arguments in C#?

The equivalent of inout in C# is ref. , as shown in the following

example: public void MyMethod (ref String str1, out String str2)

{

...

}

When calling the method, it would be called like this: String s1;

String s2;

s1 = "Hello";

MyMethod(ref s1, out s2);

Console.WriteLine(s1);

Console.WriteLine(s2);

Notice that you need to specify ref when declaring the function and calling it.

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Sep 14th, 2004
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sahu
Profile Answers by sahu Questions by sahu

Jan 10th, 2006

Ans:
Answer:
The equivalent of inout in C# is ref. , as shown in the following
example: public void MyMethod (ref String str1, out String str2)
{
...
}
When calling the method, it would be called like this: String s1;
String s2;
s1 = "Hello";
MyMethod(ref s1, out s2);
Console.WriteLine(s1);
Console.WriteLine(s2);
Notice that you need to specify ref when declaring the function and calling it.