andrewt

 Profile Answers by andrewt 

• Feb 1st, 2007

 

die: outputs stderr then exit and also it can trap errors by evalexit: just exits or exit with EXPR

nitashaa

 Profile Answers by nitashaa 

• Jul 15th, 2008

 

die("couldnot open filen"); ---> terminate the program with customized message.
die -> terminates with last system error message.
exit(0) or exit; for success 
exit(1); failure
die function never accepts number as argument.It always accepts string or nothing.
die function always terminate prgram with error message wheras exit just terminates

wow_suraj

 Profile Answers by wow_suraj 

• Jun 17th, 2009

 

1) die is used to throw an exception (catchable using eval).
exit is used to exit the process.

2) die will set the error code based on $! or $? if the exception is uncaught.
exit will set the error code based on its argument.

3) die outputs a message
exit does not.

felix

• Nov 21st, 2011

 

There is not same it must be difference . I am sure it must difference but same action perform.but returning a value difference may be like string variable what ever may be

vasava pv

• Oct 7th, 2012

 

die function was print a error message and exit function does not ... Otherwise both are same functionality

vinod

• Jun 20th, 2013

 

exit will simply end the program but die will print the message before ending the program

george

• Oct 11th, 2013

 

Die will print a message to the std err, then exit with a non-zero return code. You dont control the return code and you are stuck with the text going to the std err.

Exit will terminate with a specified return code.

I recommend a print and exit instead of a die. For instance,

print "descriptive text
";
exit(18);

You get to control if the text goes to std err or out or a log. You can also control the return code value. Die is fast and convenient, but print and exit give you much more control.