In Unix what is UMASK Value? Is it octal form or decimal form? And when we give permissions in chmod, as 644, is this 644 in octal or decimal. Does any conversion happen inside the kernel to do this? I am confused about this ....

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Nov 22nd, 2006
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Beemakonda

Nov 23rd, 2006

UMASK values is 0002, I hope this is octal form1st 0 ---> stick bit is for .exe file2nd 0 ---> user3rd 0 ---> group4th 2 ---> othersstick bit is for .exe file. If any exe file is set with the stick bit for the 1st time loads from the harddisk into the swap memory (part of Kernel) And then transaction starts. For the nexttime os will take the exe file from the swap memory and then transaction starts. For everytime of request need not to contact the harddisk that improves performance of os.