Three couples are playing golf together. The men are E, B & T while women are M G &H. they play 8 rounds.M, G, H & E score 106, 102, 100, 94 respectively. while B & T scored either 96 or 98 as it was unresolved dueto error at scoreboard. When finally resolved they found that two of the couples scoredsame. It is given that-E's wife scored greater than B's wife. Who's whose wife & how much the men scored each?

uma200026

 Profile Answers by uma200026 

• Jan 22nd, 2007

 

E wife is G

B wife is H

T wife is M

scores of men are E-94,B-96,T-98

kartikhere

 Profile Answers by kartikhere 

• Sep 11th, 2010

 

MEN- { E,B,T}

WOMEN-{M,G,H}

it is said that two of the couples scored same , so it must be 'ME' & 'GT'

 ME(106+94= 200)

 GT(102+98=200)

therefore the othr couples defenitely are 'HB'(100+96)

so the final answer is M wife of E, G wife of T, H wife of B.

am i correct?

pankajray82

 Profile Answers by pankajray82 

• Sep 18th, 2010

 

man     women
E  vs       G
B    vs     H
T    vs     M

in the copple E vs G or B vs h both copple has achive same score 196,196