A train blows a siren one hour after starting from the station. After that it travels at 3/5th of its speed it reaches the next station 2 hours behind schedule. If it had a problem 50 miles farther from the previous case,it would have reached 40 minutes sooner. Find the distance between the two stations

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shiv kumar chaudhary

Aug 1st, 2006

the eqn are :
let right time taken by train is t speed v and the distance after 50 miles to second case from the 2nd station is d then
(v*1 + 50 + d) / v= t; ==> t - 1 = (50+d)/v;
t + 2 = 1 + (d+50)/(3v/5);
t + 4/3 = 1 + 50/v + d/(3v/5);
solving these the distance b/n station is = v + 50 + d ml (all are in std unit)