Main(){ char *p = "hello world"; p[0] = 'H'; printf("%s", p);}

gau_bhatnagar

 Profile Answers by gau_bhatnagar Questions by gau_bhatnagar

• Jan 3rd, 2006

 

Answer is B) Hello World.p[0] is just replacing the value on the first index.

mef526

 Profile Answers by mef526 

• Feb 13th, 2006

 

This is generally true, except ion many embedded systems, where the static allocation to a pointer will end up in the constant, non volatile (that is, non-modifiable ROM) memory. In that case it could give either a complile error, or a runtime error if the compiler is not good enough to catch th modification of nonvolitile memory

paulson paul chambakottukudyil

• Apr 18th, 2006

 

It will give a run time error.

Anup Kumar Saha

• Nov 6th, 2006

 

hi...all.......this program will show segmentation fault.

p.b.sonawane

 Profile Answers by p.b.sonawane 

• May 8th, 2008

 

Basically, this will result in runtime error. Because when you use statement like:

char *p = "Hello world";

The space for hello word gets created in code segment only which can not be modified.

sourabh_t

 Profile Answers by sourabh_t 

• Aug 12th, 2008

 

Run Time Error

linuxgirl

 Profile Answers by linuxgirl 

• Aug 21st, 2008

 

My answer will be "Hello world".

because you have to convert it in the index.

sittoop

 Profile Answers by sittoop 

• Feb 25th, 2009

 

Latest compilers will give a warning saying
warning: deprecated conversion from string constant to ‘char*’
and it is a Segmentation fault.

jbode

 Profile Answers by jbode Questions by jbode

• Jun 30th, 2010

 

The behavior is undefined (6.4.5.6).  It may or may not result in a run-time error.