Main(){ int i, j; scanf("%d %d"+scanf("%d %d", &i, &j)); printf("%d %d", i, j);}

A) Compile error
B) 0, 0
C) Runtime error.
D) the first two values entered by the user
Explanation: two values entered, 3rd will be null pointer assignment

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Dec 10th, 2005
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Showing Answers 1 - 5 of 5 Answers

ashokiisc
Profile Answers by ashokiisc

Feb 1st, 2006

HiIn the statement scanf("%d %d"+scanf("%d %d", &i, &j)); the first two values are read into i and j. for the third value it is a null pointer assignment. so segmentation fault occurs at run time.--ashok kumar tellakula

Noor
Profile Answers by Noor

Feb 14th, 2006

first two values entered by the user.

rajeevns
Profile Answers by rajeevns

Jun 8th, 2009

Suppose if we give 1,2,3 as input, we will get
3,2
as output

abhimanipal
Profile Answers by abhimanipal

Jan 28th, 2010

I am also getting a seg fault but I am unable to understant the reason

jbode
Profile Answers by jbode Questions by jbode

Jun 30th, 2010

The behavior is undefined. There are not enough arguments for the given conversion specifiers in the scanf() calls (7.19.6.2.2). It looks like the intent is for the inner call to scanf() to offset 2 characters into the first conversion specifier, effectively giving a call of scanf(" %d"), which invokes undefined behavior (assuming that even works; odds are it doesn't in general).

Since the behavior is undefined, any of the listed results are allowed.