A s/w eng. returns from America. As he is fat he decided 2 have evening walk daily, He started at 3p.m.. He walks along the road at 4 km/hr for sometime. When he climbes a upward slope area at 3km/hr then downwards at the rate of 6km/hr. then back to the home thro the same road at 4 km/hr What is the distance he coverered in one way if he reaches back home at 9p.m.

What is the distance he coverered?
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suman

  • Nov 29th, 2005
 

24

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vivek dixit

  • Jan 28th, 2006
 

sorry............ suman u r not right..... it will b 6 km. as................ let 'a' b the dist. travelled on land..... and 'b' the dist. travelled on hill..... so----------- time for land = a/4 + a/4 = a/2 time for slope = b/3 + b/6 = b/2 so.............. (a+b) / 2 = 6 km so this is the total distance travelled on one side...

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sankarlal

  • Jun 29th, 2006
 

hai vivek ,

i think your assumption was wrong .if the s/w engg returns at 4km/hr then he

will take just 1hr 30min to return.now if you consider the whole way as a hill

then he takes only 2hrs to cover the total 6kms.so i can confidently say that

your answer was wrong.i will go with sumans 24kms .

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CAT homas

  • Jul 31st, 2007
 

Ans: 12 km. ( The distance covered in one way ).

Justification:  The road travels straight 6 km and then upwards 6km which makes our s/w engineer to cover the distance by 3 and 1/2 hour. Then he returns along the same road as he come downwards and straight to his home by 2 and 1/2 hour. Thus he is back at the home after walking for 6 hours.
Hence the distance covered in one way is 12 km.

----  Thomas

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