Narmadehwar Jha

• Aug 25th, 2005

 

the answer is  
39 hours' 
 
regards  
Narmadeshwar

Rekha

• Jan 4th, 2006

 

This question is not at all clear.

ANish

• Feb 1st, 2006

 

12 hours 1st face contains the totall space

sharadsharmamca

 Profile Answers by sharadsharmamca 

• Feb 20th, 2006

 

ans :: 39explain :: the digits shown in the clock are 1,2,3........12. their total sum is 1+2+3+....12 = 78. since it is given that sum of one bigger part is equal to total sum of another 2 smaller parts.=> bigger part = 78/2 = 39.

PRAVEEN KUMAR

• Mar 27th, 2006

 

actuallly the give condition is (2*smaller part)+bigger part = totoal sum of hoursthen solving we get 78/4=19.5 hours the small part will be 19.5,and the bigger part will be 39..... i think this the right answer....

dheepti

• Sep 15th, 2006

 

the clock normally has 12 hr

three parts x,y,z

x+y+z=12

x=y+z

2x=12

x=6

so the largest part is 6 hrs

sanjay

• Oct 10th, 2006

 

i gues you got to read the question again.. they have asked total of the hours deepthi..

suganya

• Feb 16th, 2007

 

let x be the bigger part  y and z  are  smaller parts
x+y+z=78 and x=y+z so sub y+z=x in x+y+z=78  we  get  2x=78
so x=78/2=39
Ans is 39

ramesh

• May 31st, 2007

 

answer is 39 hrs i think  6hrs is answer but in question he asked total no of hrs

so answer is 39

Vaibhav Pate

• Jun 4th, 2007

 

Normally the clock is having 12-Hours clock.
Hence no. of hours = 12.
The given condition is
   hr1 + hr2 + hr3 = 12   &    hr2 + hr3 = hr1
So, 
   2 * (hr2 + hr3)  =  12
   hr2 + hr3  =  6
i.e. hr1 = No. of hours in first part = 6 hours.

If the clock is of military pattern i.e. 24-Hours then the answer will be 12 hours.   

raja_prasanna

• Aug 18th, 2007

 

Largest part of the clock is 6 hours.

Rameshsam

 Profile Answers by Rameshsam 

• Sep 1st, 2007

 

hey guyz they didnt ask the no of digits.,
they ask for total no. of hours.,
1+2+...12=78;

x1+x2+x3=78;
gn: (x1+x2)=x3;
so,
2*x3=78;
78/2=x3;
so, x3=39;

Ans:39;

sarat_619

 Profile Answers by sarat_619 

• May 18th, 2008

 

6 hrs

kuruppushyam

 Profile Answers by kuruppushyam 

• Aug 20th, 2009

 

a+b+c=78

a=b+c
then subsitute a in place of b+c we get 2a=78, the answer is 39

manojthesingham

 Profile Answers by manojthesingham 

• Dec 4th, 2009

 

Sum of 1+2+3+4+5+6+7+8+9+10+11+12 = (12*13)/2 = 78

X + Y + Z = 78

Y + Z = X

2X = 78

X = 39[10,11,12,1,2,3]