Give the pinout & functional block diagram with the parts and controls.

rajeev kumar

• Feb 7th, 2007

Locality of reference means refering a particular area of memory while allocating variables.Whenever we allocate variables they are stored in a particular area this phenomenon is called locality of reference.

vijay

• Dec 14th, 2006

Definition of: locality of reference Also known as "locality in space" and "spatial locality," it refers to the fact that most instructions in a program are in routines that are executed over and over...

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swatias

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• Jan 11th, 2007

Mantisa  range = + 2 ^ 23 to - 2^23Exponent range = 127 to - 126so total number range will be +2^23 * 10^127 to - 2^23*10^-126

santos

• Aug 30th, 2006

-126

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sumanyaram

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• Dec 5th, 2006

Sorry it is +23 onesX(2^127) and -23onesX(2^127)i bit for sign so only 23 bits

sumanyaram

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• Dec 5th, 2006

mantissa=24 bits , exponent=8 bitsfirst consider the exponent,range is -128 to +127second consider the mantissa , max is all onesso ans is: 24 ones X (2^127) is the max positivenumber -2...

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sumanyaram

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• Dec 5th, 2006

Praveen is right,1101 is not a valid BCD number........

Danny John

• Aug 8th, 2006

Praveen is right. we are supposed to do exactly what he did. For verification convert them to decimal that is 9 + 4 =13 that is in BCD it is 0001 0011.

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sumanyaram

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• Dec 5th, 2006

5 flipflops r enough to divide the frequency by 32

S

• Aug 15th, 2006

32=2^5 => 5 bit longNumber divisible is 2*5=10 bit longQuotient & Remainder both are 5 bit eachso total 25 flip-flops at least (+ may be some other auxilliary register also)

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smokindesi

• Oct 9th, 2006

could be anywhere in memory. You can get the address from the location in IVT (assuming this subroutine is not chained) based on service number (i.e Interrupt no)location of address (i.e pointer)is available at 4*(interrupt serviced)

vikas s kulkarni

• Aug 3rd, 2005

It is stored in interrupt vector table

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Danny John

• Aug 8th, 2006

I think the output remains the same because it violates both setup time and hold time that is the input should remain constant for the setup time before the clock pulse and constant for the hold time after clock pulse provided it is edge triggered.

Ramachandran P.R

• Apr 30th, 2006

Ans is for positive edge triggerd flipflop out put:0 and for negative edge triggered output:1

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Danny John

• Aug 8th, 2006

512 adresses and 4 bit word. Hence 2048 bits.

bharti

• Jul 13th, 2006

Bytes or Bits ??

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Danny John

• Aug 8th, 2006

Since Y=C'BA'+CB'A+CBA on simplification yields Y=C'BA' + CANow it depends on the multiplexer we are using. If 8:1 MUX is used then just use A, B, C as select lines and the output of the truth table a...

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Ramachandran P.R

• Apr 30th, 2006

PLL stands Phase Locked Loop and it consists of phasedetctor,lowpassfilter,error amplifier,voltage controlled oscillator

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vishal herode

• Dec 14th, 2005

Interrupts

vishal herode

• Dec 14th, 2005

Interrupts

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Venkataramana kotakonda

• Nov 30th, 2005

Four test vector are required. To test 'struck at 0' fault  111 is the input test vector and to test 'struck at 1' fault 110 , 101 ,011 are the input test vectors.

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vikas s kulkarni

• Aug 3rd, 2005

Actually question is about controller ,controller first aserts intr signal  then after receiving intra continues the communication 

nanna kumar

• Jun 29th, 2005

when interrupt occur controller finish its current executing operation. It store the address of the next instruction. jump to IVT(intrrupt vector table).where add of ISR(int.service routine)...

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Gopi

• Jun 1st, 2005

8416 - 2A16 = 5A00

Sathyagopi

• Jun 1st, 2005

8416 - 2A16 = 5A00

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