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How to call C++ code from C ?
How can I call my C++ code from C code can you point me to some examples that are explained in detail.ThanksAjit
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# define prod(a,b)=a*bmain(){int x=2;int y=3;printf("%d",prod(x+2,y-10));}the output of the program isA. 8B. 6C. 7D. None
Rohan
- Feb 23rd, 2006
Ans is ( D ) Macro just Substitutes its arguments so ,prod ( x + 2 , y - 10 ) will be substituted by 2+2*3-10 so ans is 2+6-10=-2 None of the list given has ans is -2has ans is ( D )
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In the following code; #include<stdio.h> main() { FILE *fp; fp= fopen("trial","r"); } fp points to: a) The first character in the file. b) A structure which contains a "char" pointer which points to the first character in the file. c) The name of the file. d) None of the above.
shrutimitra
- Oct 23rd, 2005
B) A structure which contains a "char" pointer which points to the first character in the file.
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If the following program (myprog) is run from the command line as myprog monday tuesday wednesday thursday, What would be the output? main(int argc, char *argv[]) { while(--argc >0) printf("%s",*++argv); } a) myprog monday tuesday wednesday thursday b) monday tuesday wednesday thursday c) myprog tuesday thursday d) None of the above
shrutimitra
- Oct 23rd, 2005
B) monday tuesday wednesday thursday. Because in while loop we have (--argc) which will ensure that the loop will run for 4 times. if we want to print value of (*++argv) ,it will skip the first value of argv array.
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Point out the error in the following program main() { const int x; x=128; printf("%d",x); }
x should have been initialized where it is declared.
shrutimitra
- Oct 23rd, 2005
We can not assign a value to a const variables. we can only initialize it while creating or declearing the variable.
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Point out the error in the following program main() { int a=10; void f(); a=f(); printf("n%d",a); } void f() { printf("nHi"); }
The program is trying to collect the value of a "void" function into an integer variable.
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else
printf("I hate U");
}
">Iii) main(){ float me = 1.1; double you = 1.1; if(me==you)printf("I love U");else printf("I hate U");}
I hate UExplanation:For floating point numbers (float, double, long double) the values cannot be predicted exactly. Depending on the number of bytes, the precession with of the value represented varies. Float takes 4 bytes and long double takes 10 bytes. So float stores 0.9 with less precision than long double.Rule of Thumb: Never compare or at-least be cautious when using floating point numbers with...
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">X) main(){ printf("%x",-1
fff0Explanation :-1 is internally represented as all 1's. When left shifted four times the least significant 4 bits are filled with 0's.The %x format specifier specifies that the integer value be printed as a hexadecimal value
xeejam
- Nov 11th, 2005
Depending on the machine implementation it will result in FFFFFF0 (for 32bit ) or FFF0 (16 bit )
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}
}
">Main(){ int i; clrscr(); for(i=0;i
A) 1, 2, 4, 8, 16B) 0, 1, 2, 4, 8C) 0, 1, 2, 3, 4D) 5, 4, 3, 2, 1Explanation: L does't make any diff.
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