Jyoti Mittal

• Jun 9th, 2017

Yes we can

Skk

• Apr 10th, 2017

You are missing static keyword in main method, that is why error is there.
public static final void main(String[] args) {
}

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Prashant Shingne

• Sep 9th, 2016

There are 4 ways to create object
1.New Operator Employee emp = new Employee();
2.Object.clone()
3.class.forName()
4.Deserilization readObject();

Ashish

• Jun 12th, 2014

There are 7 ways to create object... 1 Using : new keyword 2 Using : Static Factory 3 Using : Instance Factory 4 Using : Factory Pattern 5 Using : De-serialization 6 Using : Clone Method 7 Using : new...

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What is the output of the following program, When tested under JDK 5.0class ExceptionDemo{ public static void main(String[] args) { int a[] = new int[] {1,2,3,4,5}; try{ System.out.prinltln(a[6]); } catch(Exception e) { System.out.println("Catching Exception ..."); } catch(ArrayIndexOutofBoundsException ae) { System.out.println("Catching ArrayIndexOutOfBounds...

kuchipudi Prasad

• May 31st, 2012

Output is "catching exception"

sampra

 Profile Answers by sampra Questions by sampra

• Mar 6th, 2012

This will give error that exception caught already

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Manjunath_7_89

 Profile Answers by Manjunath_7_89 Questions by Manjunath_7_89

• Mar 25th, 2016

Abstract Class
1. Could be Inherited.
2. Couldnt instatiated.
3. Could add few more methods.
4. Incomplete class

Final Class
1. Final version of Class
2. Couldnt be inherited.
3. Could be instantiated.
4. Couldnt add any more methods.

baban

• Feb 11th, 2016

Abstract class cannot create object but final class create a object
abstract class which have must a subclassed but final class which have no subclassed

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YUVARAJ

• May 11th, 2012

Array is a set of related data type and static whereas vector is a grow able array of objects and dynamic

sampra

 Profile Answers by sampra Questions by sampra

• Mar 13th, 2012

AL-non legecy/methods are not sysnchronized
Vector-legecy/method are synchronized

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KanikaKG  

 Profile Answers by KanikaKG Questions by KanikaKG

• Member Since Jul-2008 | Aug 4th, 2008

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No. Java is not 100 % Pure OOP because of following three reasons:
1) It doesnot support Multiple inheritance.
2) It allows use of primitive data types which are not an objects.
3) It allows static methods to call without creating the instance.

This disobeys OOPs concepts?
Java isnt 100% pure OOPS coz if it were then everything should be classes and objects, whereas java still has primitive data type which violates the above said statement...SmallTalk is the only 100% pure OOPS language

Chaitra

• Jun 6th, 2019

Java is not a pure object oriented programming language because of the primitive data type.
But java can be made 100% object oriented programming language by making use of wrapper classes.

Amit Kumar

• May 21st, 2018

Sorry, I am completely agree that java is a pure object oriented language. First of all answer me one question , what do you mean by object oriented programming ? object oriented programming is a conc...

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nik7i

 Profile Answers by nik7i Questions by nik7i

• Aug 28th, 2011

There are 3 objects created
According to syntax

string s1= new string("abcd")
syntax create an object of string

hence there are 3 object

ganga24473

 Profile Answers by ganga24473 Questions by ganga24473

• Aug 26th, 2011

One object will be created

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What is the output of the following program?class A{ public static void main(String[] s) { System.out.println(s[1] + s[2] + s[3]);}}java A 12345Options(i) 1(ii) 12(iii)1234(iv)234(v) Compilation Error

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abuthahir.d  

 Profile Answers by abuthahir.d Questions by abuthahir.d

• Member Since Jan-2008 | Apr 14th, 2008

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Khadar , i tried this code . it gives that exception

for the foll reason : 
 when u give a CLA(command line argument) , it will be inserted in the index 0 of the array and then will proceed to 1 ,2 ....

so as per the question , "12345" will be at s[0] . and length of that aray will be 1when u try to access s[1] , we are trying for 2nd element which is unavailable..... 


Hope this answers u  :-)

shyamasundar

• Jun 2nd, 2018

(v) Compilation Error

shani

• Mar 14th, 2018

(v) Compilation Error

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ashish_setia  

 Profile Answers by ashish_setia Questions by ashish_setia

• Member Since Oct-2006 | Oct 3rd, 2006

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check out this example

class Checkmain{
public static void main(String args[]){
args[1]="ashish";
System.out.println("hello ");
}
}
class Checkmain1 extends Checkmain{
public static void main(String args[]){
System.out.println("how r u");
}

}
class Jo{
public static void main(String args[]){
String S[]=new String[10] ;

Checkmain.main(S);
Checkmain1.main(S);
}}

vivek

• Aug 26th, 2017

Yes you can only do that by overriding main method signature for eg main(String[] args) to main(). Certainly there are no other ways to do that because JVM needs strings array arguments to take comma...

Dharmendra Singh

• Sep 15th, 2016

yes we can"java public class HelloWorld { // arguments are passed using the text field below this editor public static void main(String[] args) { String []s =new Str...

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