Datatypes Justify Output

#include
void main()
{
float a=0.7;
if(a<0.7)
printf("yes");
else
printf("no");
}
what is the answer and reason.

Questions by patchillaramkumar

Showing Answers 1 - 5 of 5 Answers

pavan.mustyala

  • Apr 11th, 2008
 

All floating point values are stored as double. So in the given program the value of variable "a" is interpreted as 0.69999999 thus "double" is truncated to "float".

Even Some compillers will generate a warning as follows :

initializing' : truncation from 'double' to 'float'

This is one possible reason for the wrong output.

NOTE : Also during condition checking , there will be implicit type conversion among the different data types and their values thus leading to unexpected results.So one should be very careful when checking for variables of different data types.

The if condition in the above can be modified as

if(a < (float)0.7) to get the correct output(expected output).

shweta mathur

  • Jun 6th, 2008
 

When
a = 0.7
internally compiler treats 0.7 as double.
Now a is a float and float is always small then double so the if condition is true and answer will be

YES

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gauravmitbhu

  • Jul 31st, 2009
 


#include<stdio.h>
#include<conio.h>


void main(voif)
{
float a=0.9,b=0.9;
double c=0.9;
if(a<b)
printf("yes for b");
else
printf("no for b");

if(a<c)
printf("nyes for c");
else
printf("nno for c");

getch();   
}

Output:
no for b
yes for c

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