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anirban_goswami
No. of cats = x(say)
Therefore, no. of mice killed by each cat = 999919/x (since, they killed equal no. of mice)
Now, given that
(999919/x) is greater than x, i.e
999919/x > x, implies x*x<999919
Therefore, x < 999.95(approx). Now, the only no. which is nearest to but less than 999.95 and is a factor of 999919 is 991.
Thus, x = 991 and no. of mice = 999919/991 = 1009.
To find the number of cats.
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No. of cats = x(say)
Therefore, no. of mice killed by each cat = 999919/x (since, they killed equal no. of mice)
Now, given that
(999919/x) is greater than x, i.e
999919/x > x, implies x*x<999919
Therefore, x < 999.95(approx). Now, the only no. which is nearest to but less than 999.95 and is a factor of 999919 is 991.
Thus, x = 991 and no. of mice = 999919/991 = 1009.
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