What is the output for the following code

main{
int x=90;
float *ptr;
ptr=(float *)&x;
*ptr=50.0;
printf("%d",x);
printf("%f",*pf);
}

Though the address of i & pf are same but the value which i get when i print x is a different integer value and when *pf is printed it gives the value 50.0 .why?

Interview Candidate
May 21st, 2007
1
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Answer

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answer

Oct 12th, 2007

It is always helpful to write valid code. Your example would not compile and the output would not be readable.

1:    int x = 90;
2:    float* ptr;
3:    ptr = (float*)&x;
4:    *ptr = 50.0f;            // NOTE: 50.0 is a double, 50.0f or 50.f is a float
5:    printf( "%xn", x );    // changed to hex, added newline
6:    printf( "%fn", *ptr ); // added newline

1: assigns the local stack variable x the value 90
3: assigns ptr the address of x
4: writes the value 50.f into the memory location
5: prints the hexadecimal value of 50.f
6. prints the value as a float stored in x (which is now 50.f)

The result should be

42480000
50.000000