A moves 3 kms east from his starting point. He then travels 5 kms north. From that point he moves 8 kms to the east. How far is A from his starting point?

13kms how?

This question is related to TCS Interview

Interview Candidate
Apr 21st, 2007
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Showing Answers 1 - 7 of 7 Answers

Malathi

Aug 5th, 2007

Its 12 kms
just got it geometrically!
:)

Priyanka

Nov 27th, 2007

It should be 11 kms..
i.e. 8+3 =11
because 5 kms is the vertical distance he covered...so it wont be considered...

sanjeev yadav
Profile Answers by sanjeev yadav

Dec 8th, 2007

geometrically if we think than it should be....under-root of 156.........i.e. near about 13...

sanjeev yadav
Profile Answers by sanjeev yadav

Jan 9th, 2008

x = (underroot of )[(3+8)^2 + (5^2)]
12.2 approx 13

govind
Profile Answers by govind

Jan 15th, 2008

           c---------------------------d
           '                    8
           '5
         '
a-------'b
    3

ans will be sqrt(11sqr + 5sqr)
sqrt(121+25)
12.08

saasinvijay
Profile Answers by saasinvijay Questions by saasinvijay

Jan 21st, 2008

Its 11 kms from his starting point.

spyhari
Profile Answers by spyhari

Jan 27th, 2008

           c---------------------------d
           '             8
           '5
           '
a-------'b
     3

BD=SQRT(5^2+8^2)======9.4
AD=9.4+3=12.4

method 2:
      AC=SQRT(3^2+5^2)===5.8
     AD=5.8 + 8====13.83

Which method we need to follow?