My flight takes of at 2am from a place at 18N 10E and landed 10 Hrs later at a place with coordinates 36N70W. What is the local time when my plane landed?6:00 am b) 6:40am c) 7:40 d) 7:00 e) 8:00

This question is related to TCS Interview

Interview Candidate
Jan 4th, 2007
5
17979

Showing Answers 1 - 5 of 5 Answers

dbera100
Profile Answers by dbera100

Jan 16th, 2007

The Answer is 6:40 AM
The destination place is 80 degree west to the starting place. Hence the time difference between these two places is 5 hour 20 min. (=24hr*80/360).
When the flight landed, the time at the starting place is 12 noon (2 AM + 10 hours).
Hence, the time at the destination place is 12 noon - 5:20 hours = 6: 40 AM
--- D Bera

swati shukla

Mar 14th, 2007

THERE IS A DISTANCE OF 80 LATTITUDES BETWEEN START N END PORTS.
HENCE A TIME GAP OF 80*4=320 MIN.=320/60 hrs=5.333 hrs.
after 10 hrs the start port's time is 2am+10hrs=12pm
thus end port's local time =12pm-5.33hrs=6.67=7:07am.

This is the correct ans but hasn't been included in the options..
PLS Xplain the logic of 6:40

thanks

BMat

Mar 19th, 2007

hey SWATI, u messed up an imp thing!
1 hour = 60min.(and not 100min.!!)
so, 0.33 hr = 20 min (not 33 min)
and 0.67 hr = 40 min(not 66 min)

And Mr Bera's calculation is based on a simple caln:
360 deg of longs give 24 hrs of time diff
hence
1 deg of longs give 24/360 hrs of time diff
and 80 degs give 24*80/360hrs...........
OK??
and moreover your funda of 4 min per long is also the same!
but, my dear lady remember its long that results time diff
and lats give climate diff.
ciao,
bm

sandeep

Sep 20th, 2016

Latitudianal degree value = (10+70) = 80
Each degree time difference is, 4 minutes
So, time difference = 80 X 4 = 320mins = 5 hrs 20 mins
The time at the starting place is, 2am + 10 hrs = 12pm noon
So, destination place is, 12pm - 5hrs 20 min = 6:40 am