A bus started from bustand at 8.00a m and after 30 min staying at destination, it returned back to the bustand. the destination is 27 miles from the bustand. the speed of the bus 50 percent fast speed. at what time it retur4ns to the bustand

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Oct 3rd, 2006
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g_hemanth17@yahoo.com

Oct 4th, 2006

11am

ajay

Oct 5th, 2006

It returns at the 9:58 am

anjali

Oct 5th, 2006

plz solve this question in steps.

parmeet Singh

Oct 18th, 2006

guys this qouestion is incomplete
since it is not given at what speed the bus moved ,or somthing related to that hence there is no solution to it !

dharmendra ,vipin

Mar 10th, 2007

hi friends
this is the step by step solution:

                        a bus cover 27 mile with 18 mph in =27/18= 1 hour 30 min.
                                                and it wait at stand =30 min.
                        affter this speed of return increase by 50% so

                                                     50%of 18 mph=9mph

      Total speed of returnig=18+9=27
        Then in return it take 27/27=1 hour
        then total time in joureny=1+1:30+00:30 =3 hour
        so it will come at 8+3 hour=11 a.m.

   So Ans==11 a.m