How to convert string to hexadecimal value?(using user-defined functions)

Interview Candidate
Sep 25th, 2006
2
1714

Showing Answers 1 - 2 of 2 Answers

Preetham

Sep 26th, 2006

Use %x as format specifier while printing, the characters of string, u will get the result in hexadecimal

Swati

Jan 8th, 2007

bool StrtoHex(const char* str)
{
//If string is empty
if(str == NULL)
return false;
//Variable to indicate number is positive or negative. Default is positive
bool isNeg = false;
//Index of string
int index = 0;
int num = 0;
//If first char is '-' then number is negative
if(str[0] == '-')
{
isNeg = true;
index++;
}
while(str[index])
{
//If string is between 0 to 9;
num *=16;
if((str[index] >= '0') && (str[index] <='9'))
{
num = num + str[index] - '0';
}
else if((str[index] >= 'A') && (str[index] <='F'))
{
num = num + str[index] - 'A' + 10;
}
else if((str[index] >= 'a') && (str[index] <='f'))
{
num = num + str[index] - 'a'+ 10;
}
else
{
printf("Wrong String");
return false;
}
index++;
}
if(isNeg)
{
printf("-");
}
printf("%X",num);
return true;
}