The size of a program is N.And the memory occupied by the program is given by M=square root of 100N.If the size of the program is increased by 1% then how much memory now occupied?

This question is related to TCS Interview

Interview Candidate
Aug 23rd, 2006
5
15626

Showing Answers 1 - 5 of 5 Answers

srinu

Aug 26th, 2006

Ans : 0.5%

Srikanth

Sep 12th, 2006

pls tell me the way how u solved this
thanks

kunal

Mar 4th, 2007

given..    M=10N^(1/2)................................eqn (1)
           dM/dN=10.1/2.N^(-1/2)
          or, dM=1/2(10.N^1/2)dN/N
                dM=1/2(M)dN/N........................frm eqn (1)
             dM/M=1/2.dN/N
   put dN/N=1%.........................................frm d qs.
s, dM/M=.5%.......................Answer

Akshaya

Sep 21st, 2007

Answer is 0.5% bcoz...

take n=100 then memory m=sqrt(100n)=sqrt(10000)=100

Increase n by 1% then

n=101 then memory m=sqrt(100n)=sqrt(10100)=100.5

then memory will be increased by 0.5%