Two trains start at same time frm Bangalore & mysore. They move in opposite direction reaching the destination at one hour & four hours respct after passing one another. How much faster is one train than the other?

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riyazudeen
Profile Answers by riyazudeen Questions by riyazudeen
May 25th, 2006
5
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divya07
Profile Answers by divya07

May 26th, 2006

Ans is train is twice faster than the other train,b'coz after crossing each other
speed of train A/speed of train B=square root of(time taken by B/time taken by A)
=2:1

arp001
Profile Answers by arp001

May 26th, 2006

One train is 2 times faster than the other.
Assume distance between two station is 600 km and one train is running at speed of 100 km/h and the other at 200 km/h. After 2 hours one faster train has covered 400 km and in next 1 hour it will reach the destination. Also after 2 hours slower train has covered 200 km distance and it will reach the destination in next 4 hours.

khyati

Jul 10th, 2006

T1=1 hour                 T2=4 khs.
D1=D2 (as distance is same)
S1=D1/T1   ...............(1)
and S2=D2/T2............ (2)
S1/S2= T2/T1 (dividing 1 by 2)
        =4/1
S1=4*S2

sreedhar_28
Profile Answers by sreedhar_28

Oct 12th, 2008

let s1-peed of train from bangalore to mysore(train1)
s2- speed of train from mysore to bangalore(train2)
and x be the distance from B to M
and a be the distance from bangalore till meet point
(i.e.)train1 travels a km and train2 travels x-a km
time taken by train1 to travel a=time taken by train2 to travel x-a
a/s1=x-a/s2, s1/s2=a/x-a
time taken by train1 to travel x-a=1hr
x-a/s1=1, x-a=s1
time taken by train2 to travel a=4hrs
a/s2=4, a=4s2
therefore s1/s2=4s2/s1
s1^2=4s2^2
s1:s2=2:1
train1 speed=twice the speed of train2