An escalator is descending at constant speed. A walks down and takes 50 steps to reach the bottom. B runs down and takes 90 steps in the same time as A takes 10 steps. How many steps are visible when the escalator is not operating?

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p

  • May 3rd, 2006
 

10 steps in t1 sec

90 steps in t1 sec

but we need 50steps  50steps in 5t1 sec

ans=  (90*5t1)-(50*t1)/(5t1-t1)

      =  400/4

ans =100steps

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