A fly is there 1 feet below the ceiling right across a wall length is 30m at equal distance from both the ends. There is a spider 1 feet above floor right across the long wall equidistant from both the ends. If the width of the room is 12m and 12m, what distance is to be traveled by the spider to catch the fly, if it takes the shortest path. hi Mr.Sudheer....could u tell me the approach for this question

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vishwarupa s from RVCE

  • Mar 25th, 2006
 

Hi guys,

This is a simple question, u should have little common sense,  the answer is simple, for these type of queston no matter what might be the dimensions of the room,  in this case 30*20*20,  u need to know that the vector of two points is the shortest distance but the spider cannot fly so take the projection of the line joining these two points i.e., position of fly and spider in the room , project it onto the wall and that will be the least path which the spider should travel to catch the fly.

thanks guys,

if u find any difficulty in solveing the puzzles please send me to my e-mail.

vish85_ra@yahoo.co.in

bye.

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alok

  • Apr 7th, 2006
 

its 24 simply.

what fly is expected to do is - Go down 1' on the floor, then cross the floor and then go up.

So its 1 + 12 + 11 = 24 m

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