MAHAVEER PATIL

• Feb 3rd, 2006

 

R shall be 50% of volume asuumed for

which S is taken 25% of that same volume

prateek nayak

• Feb 26th, 2006

 

25% of the mixture has to be added in the form of R

hitesh manglani

• Feb 27th, 2006

 

ANS: 1 part of R is enough

mundadadhiraj

 Profile Answers by mundadadhiraj 

• Mar 31st, 2006

 

I think 1 part of R will do!!!!

anonymous

• Apr 13th, 2006

 

R =2 part

thus new value of R =4part

             value of S =1part

                         %=S/R*100=1/4*100=25% 

NAGARAJU

• May 2nd, 2006

 

added R is 2 parts. then total parts are 4 . in total mixure R is 3 parts and S is 1 part. then S % is 25 %.

Vijay

• May 28th, 2007

 

Answer is 1 part of r to be added.


When r is 2 parts and s 1 part the total parts is 3. so wen you add 1 part of r the total part becomes 4.Hence 1 part of s out of the total 4 parts is 25%.

Benit Amala

 Profile Answers by Benit Amala Questions by Benit Amala

• Sep 16th, 2007

 

r/2=s/1
=>r=2s
=2*.25=.5
=>2r=1part

santosh

• Sep 29th, 2007

 

Initial r=2
s=1
%s=(1/3)100=33.3
%r=66.6
to make %s=25,
33.3-25=8.3 reduce
%r=66.6+8.3=74.9=75

75=(x)100=>x=75/100=3/4
it means it is 3rd part of 4
=>1 part is added