anandarao

 Profile Answers by anandarao 

• Dec 28th, 2005

 

if they meet at t time.dist. travelled by first one I*tdist. travelled by second one H*ttotal distance is t*(I+H)=Lso t= L/(I+H)meeting point is I*t = I*L/(I+H) dist. from port

hardeep singh

• Mar 15th, 2006

 

sol- let they meet at time t. if they are moving in same direction then- I*t = H*t +Lie t = L / (I - H); ansif they are moving in opposite direction then- I*t + H*t = Lie t = L / (I + H); ans

rajitha

• Jun 22nd, 2006

 

hi,

can u plz explain the answer in detail.

thanks,

Rajitha.

RAKESH CHOUDARY

• Jul 30th, 2006

 

Hai rajitha

It involves in simple formulae, if a ship started in port with I kmph,

another ship start at a distance L km from port with a speed of H kmph

then the meeting time of both ships = L/(I-H)

at what distance they meet = t*d = l/(i-h)*i

shikhi

• Jul 23rd, 2007

 

From the port to the perticular distance is L.
So from simple maths, You can say that if (I+H) mph distance can cover in 1 hour, then l distace cancover by L/(I+H) hours.

Benit Amala

 Profile Answers by Benit Amala Questions by Benit Amala

• Sep 16th, 2007

 

How could you say that the answer is between I and J and close to J