One fast typist type some matter in 2hr and another slow typist type the same matter in 3hr. If both do combinely in how much time they will finish.

1hr 12min
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Ms Nehal

  • Dec 4th, 2005
 

Hi,

Can you please explain how does the answer come 1hr 12minutes?

please

Thanks & Regards

Nehal

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anandarao

  • Dec 27th, 2005
 

Faster one can do 1/2 of work in one hourslower one can do 1/3 of work in one hourboth they do (1/2+1/3=5/6) th work in one hour.so work will b finished in 6/5=1.2 hour i e 1 hour 12 min.

MAHAVEER PATIL

  • Feb 3rd, 2006
 

if faster does 50% work % slower one does other 50 % work will take 2and 1/2 hours time

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manjunath

  • Apr 28th, 2007
 

if faster person taking 50% of work he requires 1hr and second person will do in 1.5hrs so totally 2.5hrs.please if it wrong, forgive my fault.

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bp

  • Jun 9th, 2007
 

in 1hr, 5/6th of work is completed,then remaining is 1/6th, a& b will do work in ratio 3:2,1/10 of work is done by a,1/15 is done by b,therefore 1 hr 24min

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anil kumar

  • Aug 16th, 2007
 

Can you please explain how to you formulate this formula? 

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isha verma

  • Nov 23rd, 2010
 

It is a time and work problem
here
1/no of hours of fast typist+1/no of hours of slow typist=1/total no of hours

1/2+1/3=5/6
so total no of hours=6/5
=1.2
=1 hour 12 mins

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