Are the expressions arr and &arr same for an array of integers?

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Purvi mehta

  • Nov 8th, 2006
 

Ans:- No,&arr will store the address of array.

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yuvraj

  • Mar 13th, 2007
 

The answer is YES bcoz both arr and &arr gives the base address of an array.
You can try it by a simple example
void main()
{
 int arr[10];
 printf("%dn",arr);
 printf("%d",&arr);
}

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Jyotiranjan Moahnty

  • Oct 8th, 2007
 

#include<stdio.h>
int main()
{
 int arr[2];
 printf("%dn",arr);
 printf("%dn",(arr+1));
 printf("%dn",&arr);
 printf("%dn",(&arr+1));
}
 

Try it, I think it is the better example for you to understand that, arr and &arr is not same. Their starting address is same, but the value in that memory is not same.

I think you are a student. I appreciate, your involvement with this  kind of things.

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KishoreKNP

  • Dec 4th, 2009
 

Arr and &Arr both are same, which will return the address of first element of the array. For example

void main()
{
   char arr[10] = "Kishore";
   printf("n%u : %u", a, &a);
}
Output:
~~~~~

65516 : 65516

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Mohamed

  • May 8th, 2013
 

Actually arr and &arr are different.
arr holds the base address of the array arr[], but &arr holds the address of the entire array.
but both expressions points to the same base address.

Code
  1.   #include<stdio.h>

    2. 

  2. "%u

    3. 

  3. ""%u

    4. 

  4. ""%u

    5. 

  5. ""%u

    6. 

  6. "

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ruphaensil

  • Dec 31st, 2013
 

error...because a is undefined

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