You should declare the variable as an int, but when you pass it in you must specify it as 'out', like the following: int i;foo(out i);where foo is declared as follows: [return-type] foo(out int o) { }

bhavkins

• Aug 15th, 2007

It is true that you use out when you don't want to initialise the variable and force the called function to initialise and assign proper value.But this mechanism doesn't stop you from initialising the...

blue

• Jun 13th, 2007

You are wrong "sahu".You?pass out parameters when you don't want to initialize the variable before entering a function. But the variable must be initialized within the function.

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A) X++B) X+=1C) Both A & B

samiksc

 Profile Answers by samiksc Questions by samiksc

• Jul 11th, 2007

X=x+1 is equivalent to x+=1 except that value of x is evaluated only once.x=x+1 is not equal to x++ (not always equal as mentioned in one of the earlier comments). If x++ is a standalone statement, the two have equal effect.

dotnetrocks

 Profile Answers by dotnetrocks Questions by dotnetrocks

• Jun 21st, 2006

Performance wise both the approaches are similiar. BUt consider this statement. suppose some object obj has a variable in it as i. then, obj.1 = obj.i + 1In this case at the MSIL level u can see 2 dif...

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Skill/Topic: BeginnerA) YesB) NoExplanation: It is a reference type

poobathy

• Jun 29th, 2007

No? class? is a? reference? Type? because? its?? stored? on? heap?? and? its heap memory

shekhar

• Nov 29th, 2005

No

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A) TrueB) FalseExplanation: Assemblies can be loaded side by side

xingoflife

 Profile Answers by xingoflife Questions by xingoflife

• Jun 24th, 2007

True.Assemblies can be loaded side by side. Different versions of same assemble can be used inside a single process.Source: Professional C # 2005. Wrox edition

toyash

 Profile Answers by toyash Questions by toyash

• Mar 23rd, 2006

 Ans : FalseThe question is  " Assemblies cannot be loaded side by side " This mean its false .. you can load assemblies side by side.

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The syntax for calling another constructor is as follows: class B{B(int i){ }}class C : B{C() : base(5) // call base constructor B(5){ }C(int i) : this() // call C(){ }public static void Main() {}}

zeroKelvin71493

• Jun 18th, 2007

You need to make the constructors public ... then it will compile and run.

Raj

• Oct 19th, 2006

Wrongit has have "{}" now after the call to the base class public c1() : base() { }(atleast in .net 2.0 )

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This is currently not supported by Visual Studio .NET.

ramesh

• Jun 18th, 2007

It is not possible

sahu

 Profile Answers by sahu Questions by sahu

• Jan 10th, 2006

Ans:yes,This is currently not supported by Visual Studio .NET.

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Boogster

• Jun 5th, 2007

Boxing is converting a value-type to reference type. An example is converting an integer value to an object value.Ex:   int intValue = 10;   object obj = (object)intValue;This...

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Boogster

• Jun 5th, 2007

The New keyword just hides the base's sealed method it does not really override the method.

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In the past, you had to call .ToString() on the strings when using the == or != operators to compare the strings' values. That will still work, but the C# compiler now automatically compares the values instead of the references when the == or != operators are used on string types. If you actually do want to compare references, it can be done as follows: if ((object) str1 == (object) str2) { ... }Here's...

Rana

• May 24th, 2007

You can use a.Equals(b) to compare and return a bool value where both a and b are strings.

sahu

 Profile Answers by sahu Questions by sahu

• Jan 8th, 2006

Ans:The .NET Framework provides several methods to compare the values of strings.i am giving few methods nameLists of methodString.Compare:Compares the values of two strings. Returns an integer value....

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yatin

• May 11th, 2007

Yes abstarct class can contain sealed method. No we cannot create an abstract class without abstract method.

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You want the lock statement, which is the same as Monitor Enter/Exit: lock(obj) {// code}translates to: try {CriticalSection.Enter(obj);// code} finally {CriticalSection.Exit(obj);}

jaganmohan2

• Apr 18th, 2007

A thread is simply a separate stream of execution that takes place simultaneously with and independently of everything else that might be happening. A thread can synchronize itself with another thread...

sahu

 Profile Answers by sahu Questions by sahu

• Jan 10th, 2006

ans:yes,it is right.lock statement, which is the same as Monitor Enter/Exit: lock(obj) {// code}translates to: try {CriticalSection.Enter(obj);// code} finally {CriticalSection.Exit(obj);}

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No. However, there are plans for C# to support a type of template known as a generic. These generic types have similar syntax but are instantiated at run time as opposed to compile time. You can read more about them here.

pambatman

 Profile Answers by pambatman Questions by pambatman

• Apr 15th, 2007

Generics are a new feature in version 2.0 of the C# language and the common language runtime (CLR). Generics introduce to the .NET Framework the concept of type parameters, which make it possible to d...

sahu

 Profile Answers by sahu Questions by sahu

• Jan 6th, 2006

Ans:no

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ro_dealer

• Apr 14th, 2007

C# equivalent is : System.Text.RegularExpressions.Regex myRegex= new Regex (",(=([^""]*""[^""]*"")*(?![^""]*""))");

Abhishek

• May 31st, 2006

Does Regular Expression class depend on the language used...?

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GP

• Mar 21st, 2007

There are two easy methods1) No programming: Load the EXE/DLL with ILDASM.exe if it is .Net programed than it will work otherwise it will throw error. 2) Programatically: Use reflection API to LoadAssembly. It it is not a .Net program it will throw exception.

shailesh

• Jan 13th, 2007

Every exe is in PE(Portable executable ) form which keeps the information about in which environment it is to be run so if try to run any exe  that is not .NET complaint it will not run.

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Sung

• Mar 5th, 2007

It is "This"

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DilpreetSachdev

 Profile Answers by DilpreetSachdev Questions by DilpreetSachdev

• Mar 2nd, 2007

I think, while answering this question people are missing on the simple OO concepts. When we inherit from an Interface  say X and it has a method say do() , what you are saying is that any class...

swatias

 Profile Answers by swatias Questions by swatias

• Dec 23rd, 2006

We can inherit the methods of lx & ly interfaces using lx.method() and ly.method().Reference: http://msdn2.microsoft.com/en-us/library/ms228387(VS.80).aspx

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