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What is the syntax for calling an overloaded constructor within a constructor (this() and constructorname() does not compile)?
The syntax for calling another constructor is as follows: class B{B(int i){ }}class C : B{C() : base(5) // call base constructor B(5){ }C(int i) : this() // call C(){ }public static void Main() {}}
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Assemblies cannot be loaded side by side
A) TrueB) FalseExplanation: Assemblies can be loaded side by side
xingoflife
- Jun 24th, 2007
True.Assemblies can be loaded side by side. Different versions of same assemble can be used inside a single process.Source: Professional C # 2005. Wrox edition
toyash
- Mar 23rd, 2006
Ans : FalseThe question is " Assemblies cannot be loaded side by side " This mean its false .. you can load assemblies side by side.
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A class type in C# is a value type
Skill/Topic: BeginnerA) YesB) NoExplanation: It is a reference type
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X=X+1 is equivalent to
A) X++B) X+=1C) Both A & B
samiksc
- Jul 11th, 2007
X=x+1 is equivalent to x+=1 except that value of x is evaluated only once.x=x+1 is not equal to x++ (not always equal as mentioned in one of the earlier comments). If x++ is a standalone statement, the two have equal effect.
dotnetrocks
- Jun 21st, 2006
Performance wise both the approaches are similiar. BUt consider this statement. suppose some object obj has a variable in it as i. then, obj.1 = obj.i + 1In this case at the MSIL level u can see 2 dif...
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I was trying to use an "out int" parameter in one of my functions. How should I declare the variable that I am passing to it?
You should declare the variable as an int, but when you pass it in you must specify it as 'out', like the following: int i;foo(out i);where foo is declared as follows: [return-type] foo(out int o) { }
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Why does my Windows application pop up a console window every time I run it?
Make sure that the target type set in the project properties setting is set to Windows Application, and not Console Application. If you're using the command line, compile with /target:winexe & not /target:exe.
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What does Dispose method do with the connection object?
Deletes it from the memory.
rjempo
- Sep 9th, 2007
It is important to note that connection.Dispose() actually closes the connection first.Hence I believe it is the preferred method of destroying a connection. Given that one should really Dispose...
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Can you declare the override method static while the original method is non-static?
No, you cannot, the signature of the virtual method must remain the same, only the keyword virtual is changed to keyword override.
gptnitesh
- Sep 11th, 2007
No you cannot declare the override method static while original method is non-static, not even vice versa.
Rajesh Ravindran
- Sep 11th, 2007
No, Because the Overrirde method or Overriden method should have same access attribute, same return type, same argument etc. If it is not same it will throw compiler error.
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Is there a way of specifying which block or loop to break out of when working with nested loops?
The easiest way is to use goto: using System;class BreakExample {public static void Main(String[] args) {for(int i=0; i<3; i++) {Console.WriteLine("Pass {0}: ", i);for( int j=0 ; j<100 ; j++ ) {if ( j == 10) goto done;Console.WriteLine("{0} ", j);}Console.WriteLine("This will not print");}done:Console.WriteLine("Loops complete.");}}
jmruizsr
- Sep 18th, 2007
Yes, there are ways to break out of nested loops. Although GOTO is allowed in C#, it is normally a bad idea, bad style, and indication of lack of good software development foundation of those wh...
venkatesh
- Oct 13th, 2006
In java there is no goto operator.I think we should use label statement for that
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What is the difference between the Debug class and Trace class?
Documentation looks the same. Use Debug class for debug builds, use Trace class for both debug and release builds.
vaibhav Tyagi
- Oct 2nd, 2007
the Debug and the Trace classes are available in the Microsoft .NET Framework. You can use these classes to provide information about the performance of an application either during applicatio...
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How is method overriding different from overloading?
When overriding, you change the method behavior for a derived class. Overloading simply involves having a method with the same name within the class.
learnasp
- Oct 11th, 2007
Overriding a method involves changing the business logic og the method, however the return type and parameters remain same. However in overloading a method you can have multiple methods with same name but different signatures.
sahu
- Jan 9th, 2006
Ans:Answer: When overriding, you change the method behavior for a derived class. Overloading simply involves having a method with the same name within the class. function checkf(form) { var f = document.form1;if (document.form1.cmt.value=='') { alert('Please enter the comment'); return false; }}
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