Raghunath

• Jan 30th, 2007

Either convert both the strings to lower case / upper case before comparing

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santoshkapawar

• Jan 30th, 2007

Because it takes single line for initialization,condition check and incremention. in While loop default statement is not possible which is in for while statement must contain conditional statement which may not required in for semicolan after whie statement is allow which is allow in for

Guest

• Jan 28th, 2007

While loop excutes the certain condition untill the given condition becomes false where as in for loop we can initialise the variable, depending upon that we can specify a condition to check on every execution.

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M. PAVAN KUMAR REDDY

• Jan 30th, 2007

'while' loop can be used in two waysEntry controlled loop like:while(condition){ ...... ..... .....}In this case, the condition is checked before entering the loop. If the condition is false, th...

SMalik

 Profile Answers by SMalik Questions by SMalik

• Sep 25th, 2006

I think, the only way to use the while loop is: while(true){  --  --}

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msonia0710

 Profile Answers by msonia0710 Questions by msonia0710

• Jan 31st, 2007

Hey thanx..i was a bit confused in tht.thnx..byee

malaram

 Profile Answers by malaram Questions by malaram

• Jan 31st, 2007

Output is: 22for sizeof('a') compiler takes the ASCII value of 'a' and ASCII value is integer so answer is 2for sizeof("a") compiler also count NULL() so total characters are 2 hence answer is 2

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A function prototype tells the compiler what kind of arguments a function is looking to receive and what kind of return value a function is going to give back. This approach helps the compiler ensure that calls to a function are made correctly and that no erroneous type conversions are taking place.

Have_Phun

• Feb 3rd, 2007

Int foo(int); // This is func. prototype//Below is func. definitionint foo(int param) { int ret_val; retval=param*100;// return ret_val;}A prototype enables the compiler to know the existence of a certain function somewhere in the program.Whereas the function definition tells it's logic.

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dharmesh

• Feb 6th, 2007

Actually it is not possible to pass because we cannot predict when the interupt comes but if you store whatever data you want to pass in register just after starting your program (like in R0, R1..) and use this register value when interrupt get call, by this way you can pass.

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fcawad_03

 Profile Answers by fcawad_03 Questions by fcawad_03

• Feb 16th, 2007

General Formate of While Loop::While(Condition){ Statement; Statement;}while Loop take a terminating condition....if the conditon satisfy..then it allow to execute statement otherwise terminate the loop...

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fcawad_03

 Profile Answers by fcawad_03 Questions by fcawad_03

• Feb 18th, 2007

Conditional Compilation:::::Conditional compilation is the process of selecting which code to compile and which code to not compile. (In C and C++, conditional compilation is done with the preprocesso...

Bhushan Attarde

• Jan 22nd, 2007

There are certain directives available in c , which allows selective compilation of our code depending upon certain conditions. In short the compilation of that code depends on the condition specified...

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fcawad_03

 Profile Answers by fcawad_03 Questions by fcawad_03

• Feb 21st, 2007

I understand that some compilers pad some bytes to the aggregate data types in order to access the members of the aggregate data types(i.e. structure) fast. This depends on the architectures. Some arc...

rr

• Feb 20th, 2007

Those are 3 different things.Structure PaddingMost processors require specific memory alignment on variables certain types. Normally the minimum alignment is the size of the basic type in question, fo...

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naresh

• Feb 22nd, 2007

Hi frns the above one ans is cbecause a1 can hold only the value of s1 but not its address value........abd more over p1 cant be hold by a1 so the a1 cant become pointer to p1

winny gupta

 Profile Answers by winny gupta Questions by winny gupta

• Feb 15th, 2007

C is the wrong option as a1 is not a pointer variable

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Geek

• Feb 23rd, 2007

Void swap(int *a, int *b) {    int temp = *a;    *a = *b;    *b = temp;}

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wizard

• Feb 27th, 2007

I think u can use the files, but use "sopen" insted of "open".

Raj

• Sep 21st, 2006

Normally semaphore techniques are used when handling multiple resources. In your case you can use Mutex locks. Because you have only one file descriptor.

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c
struct Foo
{
char *pName;
};
main()
{
struct Foo *obj = malloc(sizeof(struct Foo));
clrscr();
strcpy(obj->pName,"Your Name");
printf("%s", obj->pName);
}


a. Your Name
b. compile error
c. Name
d. Runtime error

c
struct Foo
{
char *pName;
char *pAddress;
};

wizard

• Feb 27th, 2007

In first case the mem is allocated for struct but not for pName. so you will get runtime error as "Segmentation fault".In second case also you will get the same, because here allocating memory and the...

vipin gupta

 Profile Answers by vipin gupta Questions by vipin gupta

• Oct 16th, 2006

The answer to both programs is 'd' vipin

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Venky

• Mar 3rd, 2007

In  general, the return type for both printf nd scanf is integer....scanf returns no of successful inputs....printf returns no of succesful outputs....ie  in case of strings, it re...

vipin gupta

 Profile Answers by vipin gupta Questions by vipin gupta

• Oct 16th, 2006

The answer to both the programs is 'd' vipin

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Riquelme

• Mar 12th, 2007

Brankets "{}" are not necessary in case branches, since switch-case is straight flow structure. Thanks.

praveen tiwari vaishnav mcm

• Oct 14th, 2006

#include#includevoid main(){int ch;printf("enter the no");scanf("%d",&ch);switch(ch){case 1: printf(" amerika" ); break;case 1: printf("indore"); break;defoult : printf("no value"); }

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div_han

• Mar 13th, 2007

Apart from the above mentioned ones, the maximum number that could be stored in registers depends solely on the register size. The memory cannot be dereferenced by an 'addressof' operator for register variables.

shivakumara.madegowda

 Profile Answers by shivakumara.madegowda Questions by shivakumara.madegowda

• Jan 6th, 2007

Auto storage class:                                      &nb...

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gaurav_gangwar9

• Mar 17th, 2007

Ans is  3

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which one of the following is not an integral data type 1. Character 2. Boolean 3. Integer 4. Pointer type

shivakumara.madegowda

 Profile Answers by shivakumara.madegowda Questions by shivakumara.madegowda

• Mar 20th, 2007

Pointer Type is not an integral.Even though pointer type hold integer type value, It doesn't mean that. That is integer value. It is just an address of anything.

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1) If either operand of an arithmetic operator is unsigned long, the other operand is promoted to unsigned long. 2) If either operand of an arithmetic operator is unsigned int, the other operand is promoted to unsigned int. 3) If either operand of an arithmetic operator is int, the other operand is promoted to int. 4) If either operand of an arithmetic operator is double, the other operand...

ykbharat

 Profile Answers by ykbharat Questions by ykbharat

• Mar 20th, 2007

Here we cant say the default promotion without knowing the other operand.But if two operands are of different datatypes and the arithmetic operation is performed on these operands the compiler allocat...

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vijay

• Mar 20th, 2007

Ans is 4 coz n and b are undecalred. first declare them and the assign the vaue. so in the code u will get error.

Payal

• Mar 15th, 2007

Correct ans is 1. sprintf is same as printf except it stores a output to the buffer(here wer). we can say that it is opposite to atoi().

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