-
Consider the following program sigmentint n,sum=1;switch(n) {case 2:sum=sum+2;case 3:sum*=2;break;default:sum=0;} if n=2, what is the value of suma.0b.6c.3d.none
B
Bhoomika sharma
- Dec 21st, 2008
As we have n=2, thus control goes to case2: thus,value of sum becomes 3 and since there is no break stmt thus,sum is again found as (2*3)=6.Thus the value of sum is 6.
ab
- Sep 29th, 2006
Ans is d
-
Find the output of the following programmain(){int x=5, *p;p=&x;printf("%d",++*p);}a.5b.6c.0d.none
B
rizwann
- Jan 28th, 2012
This ques tests your knowledge of operator precedence and associativity
* and ++ operator have same precedence and their associativity is right to left.
That is why first (*p) is evaluated which results 5 then (++*p) i.e. (++5) is evaluated which gives us 6Meena Goel
- Sep 12th, 2007
The answer for this question is 6. in starting the value of x is 5 that will be incremented by pointer p.
-
-
'9'A. intB. charC. stringD. float
Sivakumar
- Mar 20th, 2006
'9' is a charecter constant
-
10e05A. intB. charC. stringD. float
arvind
- Oct 6th, 2006
Float
-
-
-
Identify the in correct expressionA. a=b=3=4B. a=b=c=d=0C. float a=int b= 3.5D. int a; floatb; a=b=3.5;
anon1987
- Dec 7th, 2009
Ans: D int a ; float , a=b=3.5 ; is a compound statement with necessary " ; "
chandravathi
- Dec 25th, 2005
A is incorrect. as the assignment takes place from right to left, first 3 is assigned a value of 4, which will give an error.
-
-
What is incorrect among the followingA recursive functionA. calls itselfB. is equivalent to a loopC. has a termination conditionD. does not have a return value at all
Karthik Raj
- Aug 17th, 2006
D is incorrect.Recurrsive function returns a value
-
-
Find the output of the following programmain(){int x=5, *p;p=&xprintf("%d",++*p);}A. 5B. 6C. 0D. none of these
Rohan
- Feb 23rd, 2006
Ans is ( B ) *p=5 and ++*p=++x ++x = 6 read operator precedence for more details
-
-
}
">All the programs are tested under Turbo C/C++ compilers. It is assumed that, Programs run under DOS environment, The underlying machine is an x86 system, Program is compiled using Turbo C/C++ compiler.The program output may depend on the information based on this assumptions (for example sizeof(int) == 2 may be assumed). Predict the output or error(s) for the following:i) void main(){ int const * p=5; printf("%d",++(*p));}
Answer: Compiler error: Cannot modify a constant value. Explanation: p is a pointer to a "constant integer". But we tried to change the value of the "constant integer".
-
-
Explain the need for "Virtual Destructor".
Yogini Naik
- Sep 4th, 2010
Whenever In inheritance hierarchy we access the objects of derived class by using generic pointer, and now we need to destroy the object, at this point the destructor of that class is called to w...
devi
- Jul 29th, 2006
if both the base class and derived class can have the constructors,if the derived class is to call the constructor of its own using its object,it can.but when it calls its destructor,the compiler cal...
-
How can send unlimited no of arguments to a function, eg printf function can take any no of arguments
priyapa
- Nov 15th, 2005
Using va_list variables in stdarg.h headerfile
-
What do you mean by normalisation of pointers
kbjarnason
- Jul 2nd, 2010
Generally, this term applies only in ancient DOS-based compilers when using far or huge pointers.In 16-bit DOS compilers, the default ("near mode/small mode") is to have all the data in one ...
Ahtesham Ali
- Jun 20th, 2006
Normalization functions are provided which take any of these combined types as their first argument, a pointer to the same combined type as their second argument, and place the normalization of the first into the second.
-
How to convert Stack in to Queue and v varsa ? c with data structure.
abhimanipal
- Jul 30th, 2009
Converting queue to stack. This basically means make a First in first out structure a last in first out structure. This is done by adding items in reverse11<-21<-2<-31<-2<-3<-4The ot...
abhi1983
- Jun 26th, 2006
Had it been vice versa queue to stack it would have been done easily by keeping the front pointer fixed.Simply saying by having one more function in the implementation part.But if you want to have a q...
-
strcpy(obj->pAddress, "Your Address");
free(obj);
printf("%s", obj->pName);
printf("%s", obj->pAddress);
}
">Struct Foo{ char *pName; char *pAddress;};main(){ struct Foo *obj = malloc(sizeof(struct Foo));clrscr(); obj->pName = malloc(100); obj->pAddress = malloc(100); strcpy(obj->pName,"Your Name"); strcpy(obj->pAddress, "Your Address"); free(obj); printf("%s", obj->pName); printf("%s", obj->pAddress);}
A) Your Name Your NameB) Your Address, Your AddressC) Your Name, Your AddressD) None of the aboveExplanation: Prints Nothing, as after free(obj), no memory is there containing obj->pName & pbj->pAddress
shweta
- May 16th, 2006
hi,this gives runtime error...i tried it.
C Interview Questions
Ans