-
Storage Clssses and Memory Organization
What are storage classes? Explain its memory organization?
-
How to compile a C Compiler
During developing of c language, they need to develop compiler for it,c compiler itself is written in c ok... then how did they compiled c compiler.....???????
-
-
-
-
-
Volatile Variables
Where does the variables with volatile keyword, gets stored??
-
Constant Variable Value
How will you change the value of a constant variable in C?
C Armstrong Number and multiple coding questions
Q1. write a program to find a given number is armstrong number or not ?Q2write a program which accepts a filename as a command line argument and reverse the contents of the file(i.e first character becomes the last character of the file and so on ?Q3 how can i call a function given its name as a string ?Q4 How to swap low-order byte and high order byte in an integer without using temporary variable?Q5...
How to write simple C Calender program ?
Should return the week of the date
Declare an array of N pointers
How do I declare an array of N pointers to functions returning pointers to functions returning pointers to characters?
What is a void pointer?
A void pointer is a C convention for “a raw address.” The compiler has no idea what type of object a void Pointer “really points to.” If you write int *ip; ip points to an int. If you write void *p; p doesn’t point to a void! In C and C++, any time you need a void pointer, you can use another pointer type. For example, if you have a char*, you can pass it to a function that expects a void*. You don’t...
Sum 0f 2 64 bits using 32 bits
Hi,the question is you have cpu that knows to docomputations on 32 bits(unsigned integer).write a function that find the sum of 2 64 bits numbers using this cpu?there is a struct:typedef struct{ int low;(32 bits) int high;(32 bits)}64bit;
Tricky C Program
Write a C program to find a peculiar two digit number which is three times the sum of its digits.
It looks like you are using an AD Blocker!
Please Turn OFF your ad blocker
- OR -
LOGIN to continue using GeekInterview website.
Ans