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What do you mean by normalisation of pointers
kbjarnason
- Jul 2nd, 2010
Generally, this term applies only in ancient DOS-based compilers when using far or huge pointers.In 16-bit DOS compilers, the default ("near mode/small mode") is to have all the data in one ...
Ahtesham Ali
- Jun 20th, 2006
Normalization functions are provided which take any of these combined types as their first argument, a pointer to the same combined type as their second argument, and place the normalization of the first into the second.
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How to convert Stack in to Queue and v varsa ? c with data structure.
abhimanipal
- Jul 30th, 2009
Converting queue to stack. This basically means make a First in first out structure a last in first out structure. This is done by adding items in reverse11<-21<-2<-31<-2<-3<-4The ot...
abhi1983
- Jun 26th, 2006
Had it been vice versa queue to stack it would have been done easily by keeping the front pointer fixed.Simply saying by having one more function in the implementation part.But if you want to have a q...
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strcpy(obj->pAddress, "Your Address");
free(obj);
printf("%s", obj->pName);
printf("%s", obj->pAddress);
}
">Struct Foo{ char *pName; char *pAddress;};main(){ struct Foo *obj = malloc(sizeof(struct Foo));clrscr(); obj->pName = malloc(100); obj->pAddress = malloc(100); strcpy(obj->pName,"Your Name"); strcpy(obj->pAddress, "Your Address"); free(obj); printf("%s", obj->pName); printf("%s", obj->pAddress);}
A) Your Name Your NameB) Your Address, Your AddressC) Your Name, Your AddressD) None of the aboveExplanation: Prints Nothing, as after free(obj), no memory is there containing obj->pName & pbj->pAddress
shweta
- May 16th, 2006
hi,this gives runtime error...i tried it.
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char *b = "World";
clrscr();
printf("%s", strcpy(a,b));
}
">Main(){ char *a = "Hello "; char *b = "World"; clrscr(); printf("%s", strcpy(a,b));}
A) None of the aboveB) �HelloWorld�C) �Hello World�D) �Hello�Explanation: World, copies World on a, overwrites Hello in a.
kgupta11oct
- Jul 6th, 2011
This will crash as strcpy will try to modify the content of string a that is default constant and can not be modified.Regards,Kapil
vijay sharma
- Jan 31st, 2006
This program will generate error as you are changing the contents of a const variable. as char *a ="Hello" signifies that a can point to some other location but its content can't be changed. strcpy(a,b) is copying b into a which is not allowed. So it will generate error.
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}
">Main(){ int i = 100; clrscr(); printf("%d", sizeof(sizeof(i)));}
A) none of the aboveB) 4C) 100D) 2
gau_bhatnagar
- Dec 29th, 2005
Internal sizeof(i) gives output 2.2 is integer so outer sizeof()again gives output 2.
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}
}
">Main(){ int x=5; for(;x!=0;x--) { printf("x=%dn", x--); }}
A) 5, 3, 1B) 4, 3, 2, 1, 0C) 5, 4, 3, 2,1D) none of the aboveExplanation: Infinite loop as x is decremented twice, it never be 0 and loop is going on & on
raj
- Jul 30th, 2006
Infinite LOOPx is never equal to zero
javedamaan21
- Jan 24th, 2006
The answer is an infinite loop. (5 3 1 .... )here it never goes to 0 and so condition will always be true
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}
}
">Main(){ int x=5; clrscr(); for(;x
A) 5, 3, 1, -1, 3B) 5, 2, 1C) 5, 3, 1D) None of the aboveExplanation: prints nothing, as condition in loop is false.
jasana_2006
- Dec 25th, 2006
main(){int x=5;clrscr();for(;x>= 0;x--){printf("x=%d ", x--);}}this is the correct way to print the values 5,3,1
supriya.ahire
- Mar 21st, 2006
hi, o/p is (D).It prints nothing. Though we r initializing x to 5 but in for loop it does not satisfies the condoition (x< 0),it fails.without entering in the for loop it exit from th emain program.-supriya Ahire.
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> (i - (i -1))));
}
}
">Main(){ signed int bit=512, i=5; for(;i;i--) { printf("%dn", bit = (bit >> (i - (i -1)))); }}
A) 128, 64, 32, 16, 8B) 256, 128, 64, 32, 16C) 512, 256, 128, 64, 32D) 64, 32, 16, 8, 4
sittoop
- Feb 26th, 2009
Right shift a number by 1 is equivalent to division of that number by 2^1.
Right shift a number by 2 is equivalent to division of that number by 2^2.Applying that, the answer is 256, 128, 64, 32, 16(left shift is opposite ~ multiplication)satyam_un
- Mar 13th, 2006
Ans is Bbecause the will b terminated after i=0;bit>>(i-(i-1)))means first it assignsi=5.the first value for bit is512>>(5-(5-1))=512>>1=512/2/1=256
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}
else
{
printf("OK I am gone.");
}
}
">Main(){ if (!(1&&0)) { printf("OK I am done."); } else { printf("OK I am gone."); }}
A) none of the aboveB) compile errorC) OK I am goneD) OK I am done
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If the following program (myprog) is run from the command line as myprog friday tuesday sunday, What would be the output? main(int argc, char*argv[]) { printf("%c",**++argv); }
A) mB) fC) myprogD) friday
abhimanipal
- Jul 29th, 2009
Printf("%d",argv);this prints the address of the first argumentprintf("%s",*argv); this prints the first argument myprogprintf("%c",**++argv); this prints the first character of the first argumentNow if we use an increment operator before all this we get f as the final o/p.
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What is use of macro arguments in c? what is major difference between normal macro definition and macro arguments.
kapil mandge
- Feb 25th, 2006
Macro is not inline function: we can see here...#SQR(x) x*xvoid inline SQR(int x){x*=x;}if we call macroSQR(++y) than it will work like this ++y*++y, value of y increamenting twice.but when we call inline function value is increamented only once i think that is right.
mef526
- Feb 13th, 2006
In above answer the macro SQR(4-y) doesn't work as expected. Can you see why?A macro is not an inline function, it is a text replacement done by the C preprocessor. Think of it as a search and replace with replaceable parameters.
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Main(int x).............explaination on arguments passed thr' main
shibaji paul
- Apr 20th, 2006
I am afraid, nitil goel is also partially correct. The environment parameter is not a character pointer, rather it is a array of character pointers.The actual prototype of the main function wouold be ...
nitin.goel
- Apr 8th, 2006
I think u r correct but partially as there rthree arguments not 2 third one is environmentand passed as (char *env) it gives the environment details in the programit'l help when we want to get the environment variables in our program.
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C program for command line argument
Write c program to accepts file name at command line argument and coverts all characters in the file to uppercase ?
kgupta11oct
- Jul 7th, 2011
#include "stdafx.h"#include int main(int argc, char*argv[]) {FILE* fp = NULL;char * fileName = "File.cpp"; fp = fopen(fileName,"r");char c = getc(fp);while (c != EOF) {c = toupper(c);putchar(c);c = getc(fp);}fclose (fp);return 0; }
bmlal
- Jul 14th, 2006
Int main(int argc, char *argv[]){ FILE *fp; char ch; if (argc != 2) { printf("pass two argumentsn"); exit (-1); } fp = fopen(argv[1], "r+"); if (fp == NULL) { printf("error in file openingn"); exit (-1); } ch = fgetc(fp); while (ch != EOF) { if (ch greaterThan=97 && ch lessTan
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Output of these programs.
c
struct Foo
{
char *pName;
};
main()
{
struct Foo *obj = malloc(sizeof(struct Foo));
clrscr();
strcpy(obj->pName,"Your Name");
printf("%s", obj->pName);
}
a. Your Name
b. compile error
c. Name
d. Runtime error
c
struct Foo
{
char *pName;
char *pAddress;
};wizard
- Feb 27th, 2007
In first case the mem is allocated for struct but not for pName. so you will get runtime error as "Segmentation fault".In second case also you will get the same, because here allocating memory and the...
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How will you multiply two numbers using BITWISE operators ?
thulasi
- Jul 30th, 2015
Code- #include <stdio.h>
- "
- value=%u""
- multiple the 14 bit number with 0.063""the obtained result is:&z"
vvsureshreddy
- Aug 29th, 2006
Following code snippet would do the required action:#include<stdio.h>main(){ int a,b,result; printf("nEnter the numbers to be multiplied :"); scanf("%d%d",&am...
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Why do we use header file
jintojos
- Jun 16th, 2008
Header files contains pre-compiled functions.The similar functions are grouped into same header files. These functions can be used by our programs using the icludederivative. So we can use these heade...
uddin2000
- Sep 13th, 2006
Hi, To include the functions which are not changed and which are useful for other functions For ex: I/O functions are included in the header file as they are not a part of your complier. So, we use header files to make our program easier to write
C Interview Questions
Ans