Write a program that continues to ask the user to enter any decimal number and calculate it’s binary,octal and hexadecimal equivalent.

Badugu

• Mar 11th, 2015

Please try following:

Code
#include<iostream>
#include<fstream>
#include <bitset>
"Enter a decimal Number:""Hexa Decimal:"<<std::hex<<i<<"     Octal:""Binary:""Enter a decimal Number:"

rohit suri

• Sep 11th, 2014

Code
 

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Public, protected and private are three access specifiers in C++. 1. Public data members and member functions are accessible outside the class.2. Protected data members and member functions are only available to derived classes.3. Private data members and member functions can’t be accessed outside the class. However there is an exception can be using friend classes.

ankit

• Jun 26th, 2015

Can we use protected specifier first than public than private in a class definition in c++ by making class

KomalUpadhyay

 Profile Answers by KomalUpadhyay Questions by KomalUpadhyay

• Nov 14th, 2009

Private Protected and Public all these are access specifiers.Private Data Members are only available inside classProtected Data Members are  only available inside class as well as in derived classes.Public Data members are available everywhere

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Answered by: Kranthi Kiran

• Dec 2nd, 2006

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We cannot use a 'static variable' declared in one file and use it in file 2.Reason: The purpose of 'static' keyword is to retain the value betwwen the function and to restrict thescope of the variable to the file.When a variable is declared as static it will be given memory in global area portion of the process segments with the variable mname prefixed with the file namefor Example: static int k; implies it is stored as "filename.k" in global segment.so if you try to use it in another file the compiler finds the variable prefix and flags out an error.

Vineet Srivastava

• Nov 13th, 2015

Syntatically you cannot as static is meant for one file access only. But still if you want - you can do it by passing it by reference to another file through some function.

shreekant

• Nov 5th, 2015

Nice explained by Kalayama "We cant have two storage specifiers for a single Variable declaration. If one needs to use the variable in multiple files, then he needs to declare it has extern." Its simple thing.

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Structure: Initially (in C) a structure was used to bundle different type of data types together to perform a particular functionality. But C++ extended the structure to contain functions also. The major difference is that all declarations inside a structure are by default public. Class: Class is a successor of Structure. By default all the members inside the class are private.

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sumitv  

 Profile Answers by sumitv Questions by sumitv

• Member Since Sep-2008 | Sep 4th, 2008

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Structure does support inheritance.

try out the following code.

#include<iostream>

using namespace std;

struct Base
{
    int A;
};

struct Derived:public Base
{
    int B;
    void display();
};

void Derived::display()
{
    cout<<endl<<"A = "<<A<<endl;
}

int main()
{
    Derived D;
    D.A = 111;
    D.display();
    getchar();
    return 0;
}

Try out private and protected inheritance as well. It works. :)

Regards,
Sumit

Sajeed Ullah

• Dec 2nd, 2016

All data members of the class is by default private,
Whereas all data members of structure is by default public.

Ashish

• Mar 24th, 2016

Beware, whatever is supported by a class is also supported by struct whether its inheritance, polymorphism, encapsulation, data hiding etc. etc. as of C++ 11. Only difference is, for a class default access specifier is private whereas for struct its public.

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Girish

• Jul 20th, 2017

We cannot have two variables with the same name in the same scope. To resolve this namespace is introduced. Namespace is a declarative region that provides a scope to the identifiers inside it. Acces...

dinu

• Oct 3rd, 2016

Suppose we have two libraries lib1 and lib2. let there is a function add() present in both of them, this function can have different meaning or functionality in both libraries but they have same name...

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Class is a user-defined data type in C++. It can be created to solve a particular kind of problem. After creation the user need not know the specifics of the working of a class.  

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Answered by: hirma

• Sep 18th, 2005

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class is a userdefined datatype which consists of attributes(datamembers) and behavior(member functions).Bydefault the members of a class is private.

Nikita

• Jan 23rd, 2018

Class is a user define data type which contains the variable and function which r of two type private and public where the public class members can be accessed from any other class but the private cla...

Atul

• Dec 18th, 2017

Class is same as structure in C, but in Class we have functions

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chethanhb  

 Profile Answers by chethanhb Questions by chethanhb

• Member Since Feb-2010 | Feb 25th, 2010

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I am one of the person who has pricked my head in understanding the above question. Let me explain in my way...

If you have virtual function or (let me take just "virtual" keyword as of now), it means that this member function can be redefined by derived class. When we have a virtual function in a class, it will have vtable (virtual table). This vtable will have the address of the virtual function which is defined in derived.
Now the point is, how you invoke the virtual function which is defined in derived class with the help of object of the class?
Once you create an object of class, vptr (virtual pointer) will be created. Which inturn will be pointing to the base address of the vtable. So now it is clear that you can invoke the virtual funtion of derived class only with an object that has created.
Now coming to virtual constructor,
If we make constructor as virtual in base, it means that it could be redefined in derived. Keep in mind that constructor is invoked during object creation (object is not created yet. still it is in the status "creating". Object will create only after executing constructor part code). Assume you are trying to create object of the class which has virtual constructor. During this process constructor of the class will be invoked. It looks for virtual keyword. Now it tries to look for virtual constructor in derived. But not possible bcz there is no vptr and no vtable avaibale at this point of time. So, when object is not created, then there is no vptr. If no vptr for this object, then how the consturtor of derived is invoked?. No address of this construtor will available in vtable.
Hence there is no point in having virtual constructor.

I believe that i have cleared your doubt.

Venkataramakrishna

• Mar 22nd, 2018

Whenever a class object is created this pointer is created just before initializing class constructor member values. If the constructor is virtual, you cannot create this pointer.

vikash tiwary

• May 11th, 2017

Virtual functions are used in order to invoke functions based on the type of object pointed by the pointer. But is not "invoked", it is called only once when it is declared. so, a constructor cannot be virtual.

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Venkataramakrishna

• Mar 22nd, 2018

Macro does not check for the data type. The inline function will check. You can enable or disable macros. in inline, depending on the requirement you can do this.

Naman

• Nov 14th, 2017

You pass some flags to the compiler to force inline or use always_inline attribute with GCC

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Krishna Kumar

• Sep 25th, 2018

There is three query for the above question, 1) Why reference object passed as parameter to the copy constructor? 2) Why pointer object is not passed as parameter to the copy constructor? 2) What r...

WinSound

 Profile Answers by WinSound Questions by WinSound

• May 31st, 2010

Copy constructor syntax:A(const A&) for the class "A"const - Indicates object passed as argument is not changed inside copy constructor so there may be 3 design possibliti...

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