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Why we can't put semicolon at the end of a class in java??
Devidas Sonawane
- Nov 9th, 2005
Semicolon is given at the end of sentence not at the end of class and class start with open brace ({) and end with the close brace (}). but for annonymous inner class we can give semicolon.
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Servlet and Jsp are similar,,how we can know in this situation better to use servlet or jsp..I want to know where do we can use servlet and Where do use Jsp?Exact difference:Servlet and Jsp..
Saradhy
- Dec 21st, 2006
Both Servlets and JSP's are using for the same purpose i.e to generat the dynamic content. We can either use Servlets or JSP's. But According to the MVC Architecture, we should have to use Servlets ...
viswanadh
- Mar 13th, 2006
A jsp is inturn a servlet. When we use jsp's the amount of code will be decreased when compared to servlets.But jsp's take more amount of processing time.Therefore we use jsp's if a jsp can satisfy the given processing criteria else notwe go for a servlet.
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Fill in the blanks :- Which method waits for the thread to die______________ ?
A) join()
parthu
- Feb 21st, 2006
answer is join() method.I have answered join() method,why it is giving wrong questions
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State true or false :- Final variables should be declared in the beginning?
A) TrueB) False
Thirumala Reddy K
- Jun 10th, 2016
Final variables should be declared in the beginning
alskor
- Mar 8th, 2006
This is wrong. final variables CAN be declared in the beginning as well as at the end of a class.so, the answer for this question is wrong.the limitation is that final variables can't be declared inside methods and can't be modified. but this is out of the scope of this question.
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Which of the following methods are methods of the Math class?
A) absolute( )B) log( )C) cosine( )D) sine( )
veena
- May 25th, 2013
Log()
harshpasrija
- Apr 15th, 2006
All are math functions but the defined name of the functions are not correct. Only correct name is log() hence ans is B
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Java is Not designed for the distributed environment of the Internet
A) TrueB) FalseExplanation: Java is designed for the distributed environment of the Internet, because it handles TCP/IP protocols.
mineshdesai
- Aug 17th, 2006
B.False Java is designed for the distributed environments as it supports TCP/IP and UDP both
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The simplest form of the for loop in Java is for(initialization; condition; iteration) statement;
A) TrueB) False
arthynatakala
- Aug 29th, 2008
The simplest form of the for loop in Java?is for (initialization; condition; incrementation) statement;
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Which of the following will change to the next directory above the current directory?
Skill/Topic: AWT & AppletsA) chDir("..");B) cd(".");C) up();D) none of the above
sujatawankhede
- Jun 15th, 2006
But when i m go for (a) .my answer is wrong..............gve me exact right answer please.
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‘super’ is a Java ____word
Skill/Topic: AWT & AppletsA) key
Thiyagarajan.N
- Mar 20th, 2007
Super keyword is used to invoke the over-ridden method in case of over riding concept. Using 'this' keyword i can get the value of instance variable to the current object.
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What are the differences between inheritence and polymorphism?
salil.kaul
- Apr 11th, 2006
Polymorphism can be classified into 2 categories:1. Overloading : When 2 or more functions of the same class performing same logical activity have same names but different signatures (type and order o...
anbarasigopu
- Feb 10th, 2006
inheritance:is the propety that allows the reuse of an existing class to build a new classpolymorphism enables the same function to behave differently on diff classes.in java its overriding
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How Linkedlist can be implemeented in java with out using collection framework?
sitaram81581
- May 22nd, 2006
// Linked List implementation without using Collection frameworkpublic class Node { int data; Node next; public Node(int data, Node next) { this.data = data; ...
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}
}
public class B{
public static void main(String args[])
{
A a=new A();
System.out.println(a.meth1());
}
}
The above code gives a compile error.It says cannot use void.If the return type is not void then it compiles sucessfully
what could be the reason?">Class A{public static void meth1(){System.out.println("Inside method 1");}}public class B{public static void main(String args[]){A a=new A();System.out.println(a.meth1());}}The above code gives a compile error.It says cannot use void.If the return type is not void then it compiles sucessfullywhat could be the reason?
Java Interview Questions
Ans