100 kw is the full load rating of the generator..... ..that means it can supply 100 kw without exceeding in specified temperature limits .that doesnt mean that it wont be able to supply a load more than 100 kw,it can but not for a longer period of time.after sometime the generator will burn out.if a load of 50 kw is connected to generator the generator will generate only 50 kw& not more than that.the generator will generate power only according to the requirement.
Dharmender
Feb 7th, 2018
Connected Load is 96kw &125kvaDG set will have run stand by unit for Hotel is suitable plz give your technical supporting answer
Mayilsamy Kasipandi
Jul 11th, 2017
The Generator produce the power is exactly what we withdraw as load. 100 kw genset can produce 1 kw to 115kw power depending upon the connected/withdrawing load. Normally the generator can produce 115% of designed rating.
Why we do not give DC supply in transformer means DC current is a direct current, so alternating flux is not produced, because input supply and flux will be same, so emf will not produced and same tim...
avdhesh sharma
Aug 2nd, 2015
Current=voltage/impedance,
When DC is applied then Z=R =>I= V/R and R is low for transformer, so I increases very high, so heating as current is not allowed to flow further and hence intuitively you c...
Current is the electron motion through external force. ? ? ? ? ? ? ?External force is applied voltage.
lalit
Sep 27th, 2014
Voltage is the driving force that causes the current to flow in the closed path of the circuit. so if there is no voltage , there would be no current in that part of the circuit across the element
Now assume any type of load; for simplicity I?m assuming it a only resistive load.
And let it be ?R? per phase.
For Delta connected load:
Calculation for per phase power; PD= I2R
Where I ? load current (per phase)
And,
I = ?3Vs/R{as line voltage of the supply is directly applied to the phase of the delta load}
So,
Pd = (?3Vs/R)2R = 3Vs2/Rwatts per phase.
For 3 phases:
P3D = 3Pd = 3*3Vs2/R = 9Vs2/R watts.
Now for Star connected load:
PS = I2R = (Vs/R)2R = Vs2/R watts
For 3 phases: P3S = 3PS = 3 Vs2/R watts
Conclusion:
P3S / P3D =3Vs2/R / 9Vs2/R = 1/3
It may be better concluded by drowing figures. If any variations, can connect to me through karan.sorout@gmail.com
RUP KAMAL KUTUM
Feb 3rd, 2018
Well first you assumed voltage per phase as Vs and Line voltage as sqrt(3) x Vs: Which is for star connection. Then, you assumed the same thing for Delta Connection(where line and phase voltages are t...
Anbumozhi R
Dec 3rd, 2017
Power is Same. Whether it is star to Delta conversion or Delta to star conversion. Power is 1:1
kVA is the unit for apparent power. Apparent power consists of active and reactive power. Active power is the share of the apparent power which transmits energy from the source (generator) to the user. Reactive power is the share of the apparent power which represents a useless oscillation of energy from the source to the user and back again.
It occurs when on account of some ?inertia? in the system there is a phase shift between voltage and current. This means that the current does not change polarity synchronous with the voltage. But the heat generated in a winding as well as the eddy current losses generated in a transformer core depend on the current only, regardless of whether it aligns with the voltage or not.
Therefore the heat is always proportional to the square of the current amplitude, irrespective of the phase angle (the shift between voltage and current). So a transformer has to be rated (and selected) by apparent power.
Raghu
Feb 9th, 2018
In transformer there is two losses
1. Iron loss
2. Copper loss
The iron loss is depands on Voltage
And the Copper loss is depands on current.
Umar Naik
Nov 26th, 2017
There are cu losses and iron losses which are not dependent on power factor thats why we rated it in KVA.
Frequency is no. of cycles per second i.e. rate of change w.r.t time. DC has constant amplitude it means no change w.r.t. time. So it has Zero frequency.
So net voltage in the primary winding will be (Vin-0) more due to which primary winding draws more current which leads to burning of winding. ... But when a particular High DC voltage is applied to th...
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